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Tamiku [17]
3 years ago
13

Plssssssssssss Solve for x: -(2/5)x + 4 20 c. x -20

Mathematics
1 answer:
Mice21 [21]3 years ago
5 0

Answer:

Step-by-step explanation:

412

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The sum of two numbers is 51 and the difference is 11. what are the numbers?
stiv31 [10]

(51 - 11) : 2 = 20

20 + 11 = 31


20 and 31

6 0
3 years ago
Edg vector operations, any help appreciated!
viktelen [127]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \: Add \:\: -6 \hat i - 6\hat j \:\:with \:\; Vector \:\; c

____________________________________

\large \tt Solution  \: :

Vector d can be represented as :

\qquad \tt \rightarrow \:  - 2 \hat i - 2 \hat j

Vector c can be represented as :

\qquad \tt \rightarrow \:  4 \hat i + 4\hat j

we have to create vector d from vector c

So, let's assume a vector x, such that sum of vector x and vector c equals to vector d

\qquad \tt \rightarrow \: x + ( 4 \hat i + 4 \hat j) =  - 2 \hat i  - 2 \hat j

\qquad \tt \rightarrow \: x  = -  ( 4 \hat i + 4 \hat j)   - 2 \hat i  - 2 \hat j

\qquad \tt \rightarrow \: x  = (-   4 \hat i  - 2 \hat  i)  + (  - 4 \hat j  - 2 \hat j)

\qquad \tt \rightarrow \: x  = - 6 \hat  i    -6 \hat j

Henceforth, in order to get vector d, we need to add (-6i - 6j) in vector c

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

8 0
2 years ago
The initial price of buzz stock is $20 per share. After 20 days the stock price is $30 per share and after 40 days the price is
Temka [501]

Answer:

s(t) = -\dfrac{t^2}{160}+\dfrac{5}{8}t+20

Step-by-step explanation:

given,

initial price of buzz stock = $ 20 per share

after 20 days

stock price = $30 per share

after 40 days

the price =  $35 per share

let say it is modeled by

y = ax² + b x + c

x = number of days

y = stock price

x = 0 y = 20

20 = a x 0 + b x 0 + c

c = 20

x = 20 y = 30

30 = 20² a + 20 b + 20

400 a + 20 b = 10...........(1)

x = 40 y = 35

35 = 40² a + 40 b + 20

1600 a + 40 b = 15...........(2)

solving equation (1)and (2)

a = - 1/160

b = 5/8

y = -\dfrac{x^2}{160}+\dfrac{5}{8}x+20

s(t) = -\dfrac{t^2}{160}+\dfrac{5}{8}t+20

hence , the above equation is multipart function

5 0
3 years ago
Part 2: Use congruency theorems to prove congruency​
Evgesh-ka [11]

Answer:  see proof below

<u>Step-by-step explanation:</u>

  Statement                      Reason

1. YO = NZ                      1. Given

2. OZ = OZ                     2. Reflexive Property

3. YO + OZ = YZ             3. Segment Addition Property

   NZ + OZ = NO

4. YO + OZ = NZ + OZ    4. Addition Property

5.  YZ = NO                     5. Substitution

6. ∠M ≅ ∠X                      6. Given

7. ∠N ≅ ∠Y                       7. Given

8. ΔMNO ≅ ΔXYZ           8. AAS Congruency Theorem

8 0
3 years ago
Read 2 more answers
With the information given, can you prove
kykrilka [37]

Answer: No

Currently we don't have enough information to prove this quadrilateral is a parallelogram. One piece of information that would be useful would be if the other diagonal is bisected. If that's the case, then we have a parallelogram (we would first prove the triangles congruent and then use the corresponding congruent angles to set up the parallel lines). Unfortunately, we only know about one diagonal being bisected, but not both, so we don't have enough info.

7 0
3 years ago
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