Answer is D.
x = 0 and x = 4
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Answer:

Step-by-step explanation:
We have the function:
![h(x)=f[f(x)]](https://tex.z-dn.net/?f=h%28x%29%3Df%5Bf%28x%29%5D)
And we want to find:

So, we will differentiate function <em>h</em>. By the chain rule, this yields:
![h^\prime(x)=f^\prime[f(x)]\cdot f^\prime(x)](https://tex.z-dn.net/?f=h%5E%5Cprime%28x%29%3Df%5E%5Cprime%5Bf%28x%29%5D%5Ccdot%20f%5E%5Cprime%28x%29)
Then it follows that:
![h^\prime(1)=f^\prime[f(1)]\cdot f^\prime(1)](https://tex.z-dn.net/?f=h%5E%5Cprime%281%29%3Df%5E%5Cprime%5Bf%281%29%5D%5Ccdot%20f%5E%5Cprime%281%29)
Using the table, we acquire:

And using the table again, we acquire:

Evaluate. Hence:

Volume of Solids
The volume of the solid is 758.83 in³
Step-by-step explanation:
Given that the cone and half sphere is hollow
The volume of the cone =
The Volume of the sphere = 
So the Volume of the half sphere =
The volume of solid = volume of cone + volume of the half sphere

Given
height h = 19 in
radius r = 5 in
= 
= 1/3 × 3.14 × 5 × 5 × 19
= 497.16 in³

= 2/3 × 3.14 × 5 × 5 × 5
= 261.67 in³
V = 497.16 in³ + 261.67 in³
= 758.83 in³
Hence the volume of the solid is 758.83 in³