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3 years ago

In which quadrant is point C located

Mathematics

1 answer:

kozerog [31]3 years ago

6 0

Answer:

Quadrant 4

Step-by-step explanation:

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What is the verbal expression for 6f^2+5f

pychu [463]

Answer:

f = 5/6 = 0.833 or f = 0

Step-by-step explanation:

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2 years ago

If you could be a doll and help me, that would be wonderful :)

NikAS [45]

The answer to this question of yours is B

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3 years ago

How to make 8/11 into and improper fraction

kogti [31]

8/11 cant be an improper fraction because the numerator is smaller than the denominator

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2 years ago

Haley makes earrings and packages them into cube boxes that measure 1/6 foot wide. how many 1/6 foot cubic boxes can she fit int

navik [9.2K]

Answer: $28\ cubes$

Step-by-step explanation:

The volume of a cube can be found with this formula:

$V_{(c)}=s^3$

Where "s" is the lenght of any edge of the cube.

The formula for calculate the volume of a rectangular prism is:

$V_{rp}=lwh$

Where "l" is the lenght, "w" is the width and "h" is the height.

We need to find the volume of a cube box:

$V_1=s^3=(\frac{1}{6}ft)^3=\frac{1}{216}ft^3$

To find the volume of the shipping box, first we must convert the mixed number to an improper fraction:

$1\frac{1}{6}=\frac{(6*1)+1}{6}=\frac{7}{6}$

Then the volume of the shipping box is:

$V_2=lwh\\\\V_2=(\frac{7}{6}ft)(\frac{1}{3}ft)(\frac{1}{3}ft)=\frac{7}{54}ft^3$

Now, in order to find the number of cube boxes can Haley fits into a shipping box, you must divide the the volume of the shipping box by the volume of one cube. This is:

$\frac{\frac{7}{54}ft^3}{\frac{1}{216}ft^3}=28$

6 0

3 years ago

The constraints of a problem are listed below. What are the vertices of the feasible region?<br>

Mamont248 [21]

Answer:

Option 4 : $(0.\frac{3}{2} ) \ , \ (0,2) \ , \ (6,0) \ , \ (\frac{9}{4} ,0)$

Step-by-step explanation:

<u>See the attached figure:</u>

To find the vertices of the feasible region, we need to graph the constraints, then find the area included by them, then calculate the vertices which is the intersection between each two of them.

As shown, the shaded area represents the solution of the constraints

So, the vertices of the feasible region are:

$(0.\frac{3}{2} ) \ , \ (0,2) \ , \ (6,0) \ , \ (\frac{9}{4} ,0)$

8 0

2 years ago

Read 2 more answers