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Mashutka [201]
3 years ago
10

Help plssssssssssssssssssssssssssss

Mathematics
2 answers:
Elenna [48]3 years ago
8 0

Answer:

Step-by-step explanation:

Substituting x and y values into the equations, we can get the equation

y = 7 -3x

slope: -3

ozzi3 years ago
5 0

Answer:

y=7-3x; m= -3; b= 7

Step-by-step explanation:

First to find the slope you use the formula m(slope)= (y2-y1)/(x2-X10

to get the values for (x1,y1) you can pick any pair of x and y values from the table and the same goes for (x2,y2). After that you plug the values into the formula for slope which gives you -3.

For example: (x1,y1) can be (0,7) and (x2,y2) can be (1,4)

m=(4-7)/(1-0)

m= -3/1

m= -3

From there finding the y value is very simple, pick any pair of x and y values for the table and plug them into the equation for slope intercept form, y=mx+b plug the x value in for x, the y value in for y, and the slope we got earlier in for m. b is the variable for the y intercept, which is what we are now trying to find. so once we have plugged in all of our values, we just simplify the equation

(0,7)

y=mx+b

7= -3(0)+b

7= b

Now that we have both our slope and y intercept we can just plug them into y=mx+b and then we have the equation of the relationship;

y=7-3x which can also be written as y= -3x+7

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4 years ago
PLS HELP IM BEGGING U
expeople1 [14]

Answer:

answer is 57.

Step-by-step explanation:

Given

m<6= x - 8

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Now

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hope it helps :)

8 0
3 years ago
Solve the following quadratic equation by completing the square ✓3x^2 + 10x + 7✓3 = 0​
solmaris [256]

\sqrt{3}x^2+10x+7\sqrt{3}=0\\\\\sqrt3(x^2+\dfrac{10x}{\sqrt{3}}+7)=0\\\\x^2+\dfrac{10x}{\sqrt{3}}+7=0\\\\x^2+\dfrac{10x}{\sqrt{3}}+\dfrac{25}{3}-\dfrac{25}{3} +7=0\\\\(x+\dfrac{5}{\sqrt{3}})^2 = \dfrac{4}{3}\\\\|x+\dfrac{5}{\sqrt{3}}| = \dfrac{2}{\sqrt{3}}\\\\x_1 =   \dfrac{2}{\sqrt{3}}-\dfrac{5}{\sqrt{3}} = -\dfrac{3}{\sqrt{3}} = -\sqrt{3}\\\\x_2 =    -\dfrac{2}{\sqrt{3}}-\dfrac{5}{\sqrt{3}} = \dfrac{-7}{\sqrt{3}} = -\dfrac{-7\sqrt{3}}{3}

5 0
3 years ago
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