The figure below shows two parallel lines intersected by a third line. What is the value of x
2 answers:
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See the attached figure to better understand the problem
we know that
1) First way to find the value of a
in the triangle ABC
<span>applying the Pythagorean theorem
AC</span>²=AB²+BC²--------> BC²=AC²-AB²-----> BC²=25²-15²-----> BC²=625-225
BC²=400--------> BC=20 units
a=BC
a=20 units
2) Second way to find the value of a
in the triangle ABD
AB²=AD²+BD²--------> BD²=AB²-AD²-----> BD²=15²-9²---> BD²=144
BD=12 units
in the triangle BDC
a=BC
BC²=BD²+DC²-----> 12²+16²----> 144+256------> BC²=400
BC=20 units
a=20 units
we know that
1) First way to find the value of a
in the triangle ABC
<span>applying the Pythagorean theorem
AC</span>²=AB²+BC²--------> BC²=AC²-AB²-----> BC²=25²-15²-----> BC²=625-225
BC²=400--------> BC=20 units
a=BC
a=20 units
2) Second way to find the value of a
in the triangle ABD
AB²=AD²+BD²--------> BD²=AB²-AD²-----> BD²=15²-9²---> BD²=144
BD=12 units
in the triangle BDC
a=BC
BC²=BD²+DC²-----> 12²+16²----> 144+256------> BC²=400
BC=20 units
a=20 units
Answer:
Step-by-step explanation:
Given
Quadratic equation is
Roots of the quadratic equation are
So, for the given equation roots are
