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3 years ago

Subtract 8/9 1/3 please and thank you

Mathematics

1 answer:

timama [110]3 years ago

5 0

Answer:

5/9

Step-by-step explanation:

first, find a common dominator. the 1/3 would turn into 3/9 if you multiply it by 3 to get that common dominator. then just subtract the numerator normally and you get 5/9 :)

sorry if my explanation doesn't make sense TwT

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Find all zeros x^3+2x^2+4x+21

dlinn [17]

Answer:

see explanation

Step-by-step explanation:

note when x = - 3

(- 3)³ + 2(- 3)² + 4(- 3) + 21 = - 27 + 18 - 12 + 21 = 0

hence x = - 3 is a zero and (x + 3) is a factor and dividing gives

$\frac{x^3+2x^2+4x+21}{x+3}$ = (x + 3)(x² - x + 7)

For zeros equate to zero

(x + 3)(x² - x + 7) = 0

equate each factor to zero and solve for x

x + 3 = 0 ⇒ x = - 3

x² - x + 7 = 0 ← solve using quadratic formula

x = (1 ± $\sqrt{1-28}$ ) / 2 = (1 ± 3i $\sqrt{3}$ ) / 2

x = $\frac{1}{2}$ ± $\frac{3i\sqrt{3} }{2}$

zeros are x = - 3, x = $\frac{1}{2}$ ± $\frac{3i\sqrt{3} }{2}$

5 0

3 years ago

Can someone please tell me the answer to x + x + y x y

irina1246 [14]

Answer:

2x+1y

Step-by-step explanation:

because a variable (the letter) is always 1, in that case 1 + 1 is 2 and 1 x 1 is 1. but since x and y are two different letters you cannot add them. hoped that helped :)

3 0

3 years ago

Julio is paid 1.4 times his normal hourly rate for each hour he works over 32 hours in a week. Last week he worked 43 hours and

nekit [7.7K]

Answer:

$r = \$14.71$

Step-by-step explanation:

Given

Normal Hour = 32 hours

Overtime = Hours above 32

Rate for Overtime = 1.4 times normal rate

Earnings = $535.62

Required

Determine the normal hour pay

First, we need to determine the hours worked overtime.

This is:

$Overtime = 43 - 32$

$Overtime = 11$

The equation that binds all the parameters is:

$Earnings = Normal\ Hour * Normal\ Rate + Overtime * Overtime\ Rate$

This gives:

$535.62 = 21 * r + 11 * 1.4r$

$535.62 = 21r + 15.4r$

$535.62 = 36.4r$

Solve for r

$r = 535.62/36.4$

$r = \$14.71$

4 0

3 years ago

A college-entrance exam is designed so that scores are normally distributed with a mean of 500 and a standard deviation of 100.

yawa3891 [41]

Answer:

The probability is 0.003

Step-by-step explanation:

We know that the average $\mu$ is:

$\mu=500$

The standard deviation $\sigma$ is:

$\sigma=100$

The Z-score is:

$Z=\frac{x-\mu}{\sigma}$

We seek to find

$P(x800)$

For P(x>800) The Z-score is:

$Z=\frac{x-\mu}{\sigma}$

$Z=\frac{800-500}{100}$

$Z=3$

The score of Z = 3 means that 800 is 3 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the conficion of 3 deviations from the mean has percentage of 0.15%

$P(x>800)=0.15\%$

For P(x<200) The Z-score is:

$Z=\frac{x-\mu}{\sigma}$

$Z=\frac{200-500}{100}$

$Z=-3$

The score of Z = -3 means that 200 is 3 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the conficion of 3 deviations from the mean has percentage of 0.15%

$P(x$