So with f(x), the equation is in slope-intercept form, which is y = mx+b, with m = slope and b = y-intercept. Looking at the equation, the slope is 5.
With g(x), you will have to use the slope formula (
) to find the slope. For this, I'll be using (1,3) and (2,5) to solve:
![\frac{5-3}{2-1}=\frac{2}{1} =2](https://tex.z-dn.net/?f=%20%5Cfrac%7B5-3%7D%7B2-1%7D%3D%5Cfrac%7B2%7D%7B1%7D%20%3D2%20)
The slope for g(x) is 2.
Now with h(x), you'll be doing the same thing as before. I'll be using points (1,14) and (7,16):
![\frac{16-14}{7-1}=\frac{2}{6}=\frac{1}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B16-14%7D%7B7-1%7D%3D%5Cfrac%7B2%7D%7B6%7D%3D%5Cfrac%7B1%7D%7B3%7D%20)
The slope for h(x) is 1/3.
In short, the function with the smallest slope is h(x), or the third option.
Answer:
Sandra need to score at least <u>56%</u> in her fifth test so that her average is 80%.
Step-by-step explanation:
Given:
First 4 test scores = 87%, 92%, 76%,89%
Average targeted = 80%
We need to find the minimum score she needs to make on fifth test to achieve average of at least 80%.
Solution:
Let the minimum score she needs to make in fifth test be 'x'.
Total number of test = 5
Now we know that;
Average is equal to sum of all the scores in the test divided by number of test.
framing in equation form we get;
![\frac{87+92+76+89+x}{5}=80](https://tex.z-dn.net/?f=%5Cfrac%7B87%2B92%2B76%2B89%2Bx%7D%7B5%7D%3D80)
Multiplying both side by 5 we get;
![\frac{344+x}{5}\times 5=80\times 5\\\\344+x=400](https://tex.z-dn.net/?f=%5Cfrac%7B344%2Bx%7D%7B5%7D%5Ctimes%205%3D80%5Ctimes%205%5C%5C%5C%5C344%2Bx%3D400)
Subtracting both side by 344 we get;
![344+x-344=400-344\\\\x=56\%](https://tex.z-dn.net/?f=344%2Bx-344%3D400-344%5C%5C%5C%5Cx%3D56%5C%25)
Hence Sandra need to score at least <u>56%</u> in her fifth test so that her average is 80%.
Answer:
Step-by-step explanation:
1/6
You can see that the two small angles are close to the 43 degree angle they are both acute while the other is obtuse. Now i'm only in Tenth grade and i read certain letters backwards so i may mix you up but i'ma try.
B should be a 40 degree angle or lower i dont know i dont have my protractor when i need it.
i cant give you the other two cause its too blury to read
Answer:
![cos b=\frac{4}{5}](https://tex.z-dn.net/?f=cos%20b%3D%5Cfrac%7B4%7D%7B5%7D)
Step-by-step explanation:
It is given that: a and b are complementary.
![\therefore a + b = 90\degree\\\\\therefore a = 90\degree - b\\\\Assuming\: sin \: ratio \: on\: both\: sides\\\\sin\:a = sin(90\degree - b)\\\\\therefore \frac{4}{5} = sin(90\degree - b)...(\because sin\:a = \frac{4}{5})\\\therefore \frac{4}{5} =cos\:b...\{\because sin(90\degree - \theta) = cos\: \theta\} \\\\\huge\purple{\boxed{\therefore cos\:b = \frac{4}{5}}}\\](https://tex.z-dn.net/?f=%5Ctherefore%20a%20%2B%20b%20%3D%2090%5Cdegree%5C%5C%5C%5C%5Ctherefore%20a%20%3D%2090%5Cdegree%20-%20b%5C%5C%5C%5CAssuming%5C%3A%20sin%20%5C%3A%20ratio%20%5C%3A%20on%5C%3A%20both%5C%3A%20sides%5C%5C%5C%5Csin%5C%3Aa%20%3D%20sin%2890%5Cdegree%20-%20b%29%5C%5C%5C%5C%5Ctherefore%20%5Cfrac%7B4%7D%7B5%7D%20%3D%20sin%2890%5Cdegree%20-%20b%29...%28%5Cbecause%20sin%5C%3Aa%20%3D%20%5Cfrac%7B4%7D%7B5%7D%29%5C%5C%5Ctherefore%20%5Cfrac%7B4%7D%7B5%7D%20%3Dcos%5C%3Ab...%5C%7B%5Cbecause%20%20sin%2890%5Cdegree%20-%20%5Ctheta%29%20%3D%20cos%5C%3A%20%5Ctheta%5C%7D%20%5C%5C%5C%5C%5Chuge%5Cpurple%7B%5Cboxed%7B%5Ctherefore%20cos%5C%3Ab%20%3D%20%20%5Cfrac%7B4%7D%7B5%7D%7D%7D%5C%5C)