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Alika [10]
3 years ago
7

I NEED HELP PLEASE!!!!!

Mathematics
1 answer:
kicyunya [14]3 years ago
7 0
For the explicit formulae, the final answers are boxed.

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HELP
Zanzabum
By looking at the formula you can see that the quadratic part is 0 if you fill in x=3 (you know, 3-3 = 0). The outcome of the formula then becomes y= 0+5.

That gives us point (3,5) as the top of the parabola. So there you go, answer A.
4 0
2 years ago
What is the total surface area of the triangular prism shown?
sesenic [268]

Answer:

24 2/5ft

Step-by-step explanation:

add all the sides together.

4ft x 2

3ft x 2      

10 2/5 x 1

=

24 2/5

6 0
2 years ago
Sierra used 4 pears and 12 apples to make a fruit salad. What is the
jolli1 [7]

Answer: 1:3

Step-by-step explanation: for every pear she uses 3 apples

6 0
3 years ago
Plz help me I really don't know
Alex
The value of the expression would be 16.25 or 16 and 1/4, because when you multiply something by 1/2, you’re basically dividing it by 2, and when you put parentheses next to a number (for example 2(4) ), it means that you’re multiplying it, and when more than one values are in the parentheses, they all get multiplied, basically distributive property.
5 0
2 years ago
find two positive real numbers such that they sum to 108 and the product of the first times the square of the second is a maximu
topjm [15]

The two positive numbers are 36 and 72 which gives a sum equal to 108 and the product of 36 and the square of 72 is a maximum.

Any integer greater than zero is considered a positive number. A positive number can either be written as a number or with the "+" symbol in front of it.

Let us consider the two positive real numbers as x and y. Then, their sum is written as,

x+y=108

Then, y=108-x

And the product is written as,

P=xy²

Substitute value of y in the above equation, we get,

\begin{aligned}P&=x(108-x)^2\\&=x(11664-216x+x^2)\\&=11664x-216x^2+x^3\\&=x^3-216x^2+11664x\end{aligned}

Now, differentiate P with respect to x, and we get,

\begin{aligned}\frac{dP}{dx}&=3x^2-432x+11664\\&=x^2-144x+3888\end{aligned}

Solving the above equation to zero, we get,

\begin{aligned}x^2-144x+3888&=0\\x^2-36x-108x+3888&=0\\x(x-36)-108(x-36)&=0\\(x-108)(x-36)&=0\\x&=\text{108 or 36}\end{aligned}

Substitute values of x in y=108-x, to get values of y.

If we substitute x=108, we get the y value as zero which doesn't give the required solution.

But, if we substitute x=36, we get,

\begin{aligned}y&=108-36\\y&=72\end{aligned}

Thus, the two positive numbers are 36 and 72.

To know more about positive numbers:

brainly.com/question/1635103

#SPJ4

4 0
11 months ago
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