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inna [77]
3 years ago
12

(3x^2+11x+12) / (x+2)

Mathematics
2 answers:
Dimas [21]3 years ago
4 0

Answer:

Step-by-step explanation:

Hope this helps you

Arte-miy333 [17]3 years ago
3 0

Answer:

(3x^2+11x+12) / (x+2)

(6x+11x+12) / 2x

17x+12 / 2x

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5x-29>-34 OR 2x+31<29
Margarita [4]
5x-29>-34
5x>-5
x>-1
x<1
2x+31<29
2x<-2
x<-1
x>1
6 0
3 years ago
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Simplify Simplify 1 ∙ x - x/1<br><br> A. x<br> B. 1<br> C. 0
Aliun [14]

Answer:

0

Step-by-step explanation:

when the term has a coefficient of, it does not have to be written.

x- X/1

The sum of two opposites equals o

So the solution would be o

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3 years ago
Pls Help! It would be very much appreciated, Thx!
Fofino [41]

Answer:

A. 30 two-point questions and 10 four-point questions

Step-by-step explanation:

30 multiplied by 2 equals 60

10 multiplied by 4 equals 40

60 plus 40 equals 100 points which is the amount of points the test is worth as stated i the question.

30 plus 10 equals 40, which is the total amount of questions in the test as stated in the question.

5 0
3 years ago
4 thousandths times 3 (like this plz 0.004x3)
Ksju [112]

Answer:

0.012

Step-by-step explanation:

0.004 * 3 = 0.012

8 0
3 years ago
What are the real and complex solutions of the polynomial equation? x^3-8=0. with imaginary numbers
seraphim [82]

Answer:

Solutions are 2,  -1 +  0.5 sqrt10 i  and -1 - 0.5 sqrt10 i

or 2,  -1 +  1.58 i  and -1 - 1.58i

(where the last 2 are equal to nearest hundredth).


Step-by-step explanation:

The real solution is x = 2:-

x^3 - 8 = 0

x^3 = 8

x = cube root of 8 = 2

Note that a cubic equation must have  a total of 3 roots ( real and complex in this case).  We can find the 2 complex roots by using the following identity:-

a^3 - b^3 = (a - b)(a^2 + ab + b^2).

Here  a = x and b = 2 so we have

(x - 2)(x^2 + 2x + 4) = 0

To find the complex roots we solve x^2 + 2x + 4 = 0:-

Using the quadratic formula x = [-2 +/- sqrt(2^2 - 4*1*4)] / 2

= -1 +/- (sqrt( -10)) / 2

= -1 +  0.5 sqrt10 i  and -1 - 0.5 sqrt10 i

4 0
3 years ago
Read 2 more answers
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