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3 years ago

(3x^2+11x+12) / (x+2)

Mathematics

2 answers:

Dimas [21]3 years ago

4 0

Answer:

Step-by-step explanation:

Hope this helps you

Arte-miy333 [17]3 years ago

3 0

Answer:

(3x^2+11x+12) / (x+2)

(6x+11x+12) / 2x

17x+12 / 2x

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Solve this equation: 4+k=11

Law Incorporation [45]

Answer:

k=7

Step-by-step explanation:

4+k=11

subtract 4 from both sides to isolate k

k= 7

3 0

3 years ago

In what year will the two quantities be equal?

Galina-37 [17]

Its the second because i did this already

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3 years ago

Which statement describes if there is an extraneous solution to the equation √x-3 = x-5? A. there are no solutions to the equati

Brrunno [24]

Remember that an extraneous solution of an equation, is the solution that emerges from solving the equation but is not a valid solution.

Lets solve our equation to find out what is the extraneous solution:
 $\sqrt{x-3} =x-5$
$(\sqrt{x-3})^2 =(x-5)^2$
$x-3=x^2-10x+25$
$x^2-11x+28=0$
$(x-4)(x-7)=0$
$x-4=0$ and $x-7=0$
$x=4$ and $x=7$

So, the solutions of our equation are $x=4$ and $x=7$ . Lets replace each solution in our original equation to check if they are valid solutions:
- For $x=7$
$\sqrt{x-3} =x-5$
$\sqrt{7-3} =7-5$
$\sqrt{4} =2$
$2=2$
We can conclude that 7 is a valid solution of the equation.

- For $x=4$
$\sqrt{x-3} =x-5$
$\sqrt{4-3} =4-5$
$\sqrt{1} =1$
$1 \neq 1$
We can conclude that 4 is not a valid solution of the equation; therefore, 4 is a extraneous solution.

We can conclude that the correct answer is: D. the extraneous solution is x = 4

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3 years ago

The mean price of a textbook is $82, and the range of prices are $16. What are the possible prices for the textbook?

Akimi4 [234]

82$ and 74$ since there is a variety of the same numbers

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2 years ago

Plz help i will give you an thank promise

Naily [24]

What is your question(s)? I can try to help you

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3 years ago