<span>B. 16 quarts of the 2% milk and 24 quarts of the 7% milk
First, let's create an equation to solve.
x = quarts of 2% milk
(40-x) = quarts of 7% milk
So we have the equation
x*2 + (40-x)*7 = 40*5
Now to solve for x
x*2 + (40-x)*7 = 40*5
x*2 + 7*40 - 7*x = 40*5
x*2 - 7*x = 40*5 - 7*40
-5*x = - 2*40
x = 2*8
x = 16
So we need 16 quarts of 2% milk and 40-16 = 24 quarts of 7%, which matches option "B".</span>
Answer:
The answer to your question is: x = -1
Step-by-step explanation:
Data
slope of l = x
slope of m = x +2
they are ⊥
Process
If they are ⊥, then, x + 2 = - 1/x
x(x + 2) = -1
x² + 2x = -1
x² + 2x + 1 = 0
(x + 1)² = 0
x + 1 = 0
x = -1
Answer:
a) 0.857
b) 0.571
c) 1
Step-by-step explanation:
Based on the data given, we have
- 18 juniors
- 10 seniors
- 6 female seniors
- 10-6 = 4 male seniors
- 12 junior males
- 18-12 = 6 junior female
- 6+6 = 12 female
- 4+12 = 16 male
- A total of 28 students
The probability of each union of events is obtained by summing the probabilities of the separated events and substracting the intersection. I will abbreviate female by F, junior by J, male by M, senior by S. We have
- P(J U F) = P(J) + P(F) - P(JF) = 18/28+12/28-6/28 = 24/28 = 0.857
- P(S U F) = P(S) + P(F) - P(SF) = 10/28 + 12/28 - 6/28 = 16/28 = 0.571
- P(J U S) = P(J) + P(S) - P(JS) = 18/28 + 10/28 - 0 = 1
Note that a student cant be Junior and Senior at the same time, so the probability of the combined event is 0. The probability of the union is 1 because every student is either Junior or Senior.
Answer:
It's D - There is a constant third difference of 24.
Step-by-step explanation:
