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MrRissso [65]
3 years ago
6

The average value of y=v(x) equals 4 for 1≤x≤6, and equals 5 for 6≤x≤8. what is the average value of v(x) for 1≤x≤8 ?

Mathematics
1 answer:
Tomtit [17]3 years ago
7 0
The average value over the interval is the area under the curve divided by the width of the interval.

Area = 4*(6 -1) +5(8 -6) = 30
Width = 8 - 1 = 7

Average value = 30/7 = 4 2/7

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REY [17]

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y = 18 / (x + 2)²

Step-by-step explanation:

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Leviafan [203]

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Step-by-step explanation:

this is the answer in simple form

8 0
4 years ago
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The area of triangle formed by points of intersection of parabola y=a(x−1)(x−4) with the coordinate axes is 3. Find a if it is k
n200080 [17]

Answer:

The value of a will be  a=-\frac{1}{2}

Step-by-step explanation:

Start by graphing the parabola and  the three points of the triangle. These points are at intersections of y=a(x-1)(x-4) and the axes

so the y = 0 points are (1,0) and (4,0).

The x = 0 intersection is when y=a(-1)(-4) or (0,4a)

The base and height of this triangle are

The base would be the distance between the y=0 intersections and the height would be the y value of the other vertex.

Hence, base=3 units and height = 4a units. Thus, area can be calculated as

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a=\frac{1}{2}

∵ the parabola opens downward therefore a will be negative.

hence,  a=-\frac{1}{2}

3 0
3 years ago
What is the value of y?<br> A.25 B.35 C.100 D.50
spin [16.1K]

Answer:

B. 35

That is the answer

Hope it helps

6 0
3 years ago
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