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3 years ago

Help and explain explain !!!!!!!!!!

Mathematics

1 answer:

tigry1 [53]3 years ago

3 0

Answer:

$x=-1\text{ or }x=11$

Step-by-step explanation:

For $a=|b|$ , we have two cases:

$\begin{cases}a=b,\\a=-b\end{cases}$

Therefore, for $18=|15-3x|$ , we have the following cases:

$\begin{cases}18=15-3x,\\18=-(15-3x)\end{cases}$

Solving, we have:

$\begin{cases}18=15-3x, -3x=3, x=\boxed{-1},\\18=-(15-3x), 18=-15+3x, 33=3x, x=\boxed{11}\end{cases}$ .

Therefore,

$\implies \boxed{x=-1\text{ or }x=11}$

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You pay $1.56 for 4 pounds of bananas. Write and solve an equation to find out how much it costs for 1 pound of bananas.

Tom [10]

Answer:

1.56 / 4 = 0.39

1 Pound of bananas cost $0.39

Step-by-step explanation:

8 0

3 years ago

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Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

3 years ago

HELP ME PLEASE, I'D LIKE TO UNDERSTAND HOW TO DO THIS TOO SO I'LL GIVE BRAINLY FOR THE RIGHT ANSWER WITH GOOD AND UNDERSTANDING

umka2103 [35]

Answer:

34 goes in the blank.

Step-by-step explanation:

Triangle ABC is congruent to triangle TUV implies the following:

Angle A is congruent to angle T.

Angle B is congruent to angle U.

Angle C is congruent to angle V.

Side AB is congruent to side TU.

Side BC is congruent to side UV.

Side CA is congruent to side VT.

Note: Order tells you everything in a congruence statement.

Since side BC is congruent to UV, then the measure of side BC is equal to the measure of side UV.

8x+2=7x+6

Subtract 7x on both sides:

1x+2=6

x+2=6

Subtract 2 on both sides:

x=6-2

x=4

So if x=4, then the measure of side BC is 8x+2=8(4)+2=32+2=34.

So the measure of BC is 34 cm.

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4 years ago

If x, y, and z are integers greater than 1, and (327)(510)(z) = (58)(914)(xy), then what is the value of x?

algol [13]

Answer:

Statements (1) and (2) TOGETHER are NOT sufficient.

Explanation:

As in the equation (327)(510)(z) = (58)(914)(xy) there are THREE variables in total i.e. "x", "y" and "z" hence minimum three equations are required to find out values of all variables. Hence,

If the given number of equations is equal to total variable used in any of the equation, values of all the variables can be find out otherwise there can be unlimited number of solutions.

So, value of "x" cannot be determined with the given data.

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3 years ago

PLEASE ANSWER AND EXPLAIN | 98 POINTS

9966 [12]

Answer:

d

0.9

The value of a correlation coefficient ranges between -1 and 1.

The greater the absolute value of the Pearson product-moment correlation coefficient, the stronger the linearrelationship.

The strongest linear relationship is indicated by a correlation coefficient of -1 or 1.

The weakest linear relationship is indicated by a correlation coefficient equal to 0.

A positive correlation means that if one variable gets bigger, the other variable tends to get bigger.

A negative correlation means that if one variable gets bigger, the other variable tends to get smaller.

hope it helps.

3 0

4 years ago

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