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solong [7]
3 years ago
8

Resolver la siguiente desigualdad : x^2 - 7x + 12 ≤ 0

Mathematics
1 answer:
stira [4]3 years ago
5 0
I hope this helps you

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Which of the following equal to 0.0326
Talja [164]

Step-by-step explanation:

0.0326 = 326/10000 = 163/5000

What are the following terms?

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4 years ago
Given the data set (200, 150, 325, 350, 100, 75), Find the range of the data set
andriy [413]
The range is just the distance between the biggest number
and the smallest one.

The biggest number on that list is  350 .
The smallest number on that list is  75 .

The range is from  75 to 350, or a distance of  275 .
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A shipping company charges based on calculations of the volume of a rectangular box and the sum of the dimensions of the box. A
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Answer:

A shipping company charges based on calculations of the volume of a rectangular box and the sum of the dimensions of the box. A square rectangular...

Step-by-step explanation:

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3 years ago
The length of an alligator in a zoo is 14 5/6 feet.The everglades national parks list the longest alligator ever reocord in flor
astraxan [27]

Answer:

The difference in the lengths of the two alligators = 3

Step-by-step explanation:

First, let us make the lengths improper fractions, then we will find the difference from there.

Alligator 1:

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To convert to improper fraction, multiply the denominator by the whole number, and then add the denominator [(12 × 14) + 5]

Alligator 2:

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Therefore the difference in the lengths of the two alligators = 3

3 0
4 years ago
What represents the inequality |x + 1| + 2 < –1.
alex41 [277]
Question is a bit vague.  If you wish to graph this inequality, you'll need to know what the graph of the absolute value function y = |x| looks like; it's a " V " with the vertex at the origin.  The slope of the right half of the graph is m=1.  Draw this function.  

Next, subtract 2 from both sides.  We'll get <span> |x + 1|  < –1 - 2
or 
</span> |x + 1|  < –3.  We can stop here!  Why!  because the absolute value function is never smaller than zero, and so <span> |x + 1| is never smaller than -3.  

You could, of course, graph y = |x+1|; start with your graph for y = |x| and then move the whole graph 1 unit to the left (away from the origin).  If you do this properly you'll see that the entire graph is above the x-axis, except for the vertex (-1,0).  Again, that tells us that the given inequality has no solution.


</span>
4 0
3 years ago
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