Answer:
0.2611 = 26.11% probability that exactly 2 calculators are defective.
Step-by-step explanation:
For each calculator, there are only two possible outcomes. Either it is defective, or it is not. The probability of a calculator being defective is independent of any other calculator, which means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
5% of calculators coming out of the production lines have a defect.
This means that 
Fifty calculators are randomly selected from the production line and tested for defects.
This means that 
What is the probability that exactly 2 calculators are defective?
This is P(X = 2). So


0.2611 = 26.11% probability that exactly 2 calculators are defective.
Answer:
It gets more complicated with a six-sided die. In this case if you roll the die, there are 6 possible outcomes (1, 2, 3, 4, 5 or 6). Can you figure out what the theoretical probability for each number is? It is 1/6 or 0.17 (or 17 percent).
Based on the above:
The slope of P'Q' is = -3/2
The length of P'Q' is approximately = ![\sqrt[3]{13}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B13%7D)
<h3>What is the polygon about?</h3>
The slope of P'Q'
= -6/4 = -3/2
The length of P'Q' =
P'Q' = 
= 
= ![\sqrt[2]{13}](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B13%7D)
Therefore;
P'Q' =
P'Q' =
x ![\sqrt[2]{13}](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B13%7D)
= ![\sqrt[3]{13}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B13%7D)
Learn more about polygon from
brainly.com/question/1592456
#SPJ1
Answer:
C. 1/4 cup for every cup of water
Step-by-step explanation: