615 - 6 = 609
963 - 6 = 957
609=3×3×29
957=3×11×29
HCF=3×29=87
The largest number that divides 615 and 963 leaving remainder 6 in both numbers is 87.
I dont know, im working it out now, or im trying to
if the 20% of a number is 386, what will be 30% of the same number
Answer will be 157
2L+2W=157.5
L=W-30
2(W-30)+2W=157.5
2W-60+2W=157.5
+60 +60
4w=217.5
W=54.4(.37 rounded to nearest tenth)
L=24.4
Answer:
see explanation
Step-by-step explanation:
the result 0 = 0
means the equation has an infinite number of solutions
