1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lana71 [14]
3 years ago
5

What means the data is still saved even if you turn the computer off or unplug it?​

Computers and Technology
1 answer:
s2008m [1.1K]3 years ago
8 0

Answer:                      

Explanation:

The hard drive is long-term storage, which means the data is still saved even if you turn the computer off or unplug it. When you run a program or open a file, the computer copies some of the data from the hard drive onto the RAM. When you save a file, the data is copied back to the hard drive.

You might be interested in
List the steps that you need to locate Microsoft Word on your computer
Olegator [25]
1.click windows start button on the bottom left corner
2. search Microsoft word
3.once Microsoft word is found right click on it
4. then you will see an option called "open file location"
5. then you will have the location of microsoft word
6 0
3 years ago
In a linked chain implementation of a queue, the performance of the enqueue operation
alexdok [17]

Answer:

A.O(1)

Explanation:

In the implementation of queue by using linked chain the performance of  the enqueue operation is O(1).We have to  maintain  two pointers one  head and the other tailand  for  enqueue operation  we have to insert element  to the next of the tail and then  make that element  tail.Which takes O(1) time.

4 0
3 years ago
1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

7 0
3 years ago
Why do people enjoy codehs
Alex73 [517]

Answer: this is a moral question, but here is my view

Explanation:

we get to learn about things like java which i am currently learning for AP computer science A

6 0
3 years ago
What are some ways to accomplish full-duplex (FDX) digital communications on guided medium at the physical layer (OSI Layer 1)?
labwork [276]

Answer:

d. All of the above

Explanation:

Physical layer is the lowest layer of the OSI reference model that deals with the setup of physical connection to the network and with transmission and reception of signals.

Full duplex (FDx) is a bidirectional type of communication system where two end nodes send and receive data signals at the same time, and a single carrier is simultaneously used for dual communication.

To send or receive data, the participating nodes in a Full Duplex system do not have to wait for a free carrier/medium. It employs a medium that has at least two internal channels - one for sending and one for receiving.

Based on the above explanations, options A, B and C are valid and are correct ways to accomplish full-duplex (FDX) digital communications on guided medium at the physical layer (OSI Layer 1). There all of them are correct.

6 0
2 years ago
Other questions:
  • ____ are the computers that store network software and shared or private user files.
    6·1 answer
  • a corporation needs an operating system that allows the various teams in its office to network &amp; collaborate on projects. wh
    11·2 answers
  • If you turn on the Lock alpha button , what happens
    5·2 answers
  • The function of the file server is to : 1. store data and software programs that can be used by client computers on the network.
    12·1 answer
  • Suppose we perform a sequence of n operations on a data structure such that if some condition C(k) holds then the kth operation
    7·1 answer
  • Precautionary measures to be observed when using ICT tools​
    15·1 answer
  • What is the primary responsibility of the federal reserve bank??
    11·1 answer
  • What is computer. Write full form of mips​
    15·1 answer
  • What is the ls option to list entries by lines instead of by columns?​
    11·1 answer
  • Write a two to three sentence response to the following question:
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!