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Bad White [126]
3 years ago
11

P - 5(p+4) = p - (8-p)

Mathematics
1 answer:
zhuklara [117]3 years ago
4 0

Answer:

Simplifying 6p + 2(4 + -2p) = 3(p + 4) 6p + (4 * 2 + -2p * 2) = 3(p + 4) 6p + (8 + -4p) = 3(p + 4) ... Move all terms containing p to the left, all other terms to the right. ... When you enter an equation into the calculator, the calculator will begin by ... Similarly, 2 * (x + 5) can also be entered as 2(x + 5); 2x * (5) can be entered as 2x(5).

Step-by-step explanation:

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Can someone plz help me solved this problem! Need help ASAP! Help me !
lana66690 [7]

Answer:  5, 8

<u>Step-by-step explanation:</u>

The difference between 3 times a number and -8 is BETWEEN 23 and 32

Note: "difference" means subtraction --> 3x - (-8)  --> 3x + 8

               23 < 3x + 8 < 32

               15 < 3x        < 24          <em> subtracted 8 from all 3 sides</em>

-->             5 <   x        <   8          <em>divided 3 from all 3 sides</em>

 

5 0
3 years ago
The American Management Association is studying the income of store managers in the retail industry. A random sample of 49 manag
VashaNatasha [74]

Answer:

a) The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

b) The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

Step-by-step explanation:

Question a:

We have to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a p-value of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96\frac{2050}{\sqrt{49}} = 574

The lower end of the interval is the sample mean subtracted by M. So it is 45420 - 574 = $44,846.

The upper end of the interval is the sample mean added to M. So it is 45420 + 574 = $45,994.

The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

Question b:

The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

5 0
3 years ago
Divide. Round your answer to the nearest hundredth 1÷3
ipn [44]
Well your going to get 0.3333333333(the 3's are infinite) :D
8 0
3 years ago
Read 2 more answers
Here are some summary statistics about the number of accounts that follow some bands on social media. mean: 15,976 followers med
Lelu [443]

Answer:

what kind of math is this

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Solve for x and state the measure of the angles with an x in them
Arada [10]

Answer:

x = 83

Step-by-step explanation:

The sum of the angles of a quadrilateral is 360

75+x+97+105 = 360

Combine like terms

x+277=360

Subtract 277 from each side

x+277-277=360-277

x = 83

5 0
3 years ago
Read 2 more answers
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