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ale4655 [162]
3 years ago
12

Simplify each expression

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
3 0
1. -4+5x^3-(-3y)^0

-1+-3=-4
3x^2+ 2x^1= 5x^3
9y^1-6y^1=14y^0

2. 2y-(-3x^5)+10

5y-3y=2y
-3x^1+-2x^2=-5x^3
-5x^3+2x^2=-3x^5

3. 3x+3y+8

4x^2+2x=6x^3
6x^3-3x^2=3x
7y-2y=4y
4y-y=3y
-5+(-3)=8

4. 6x^3+4y+2

3x^2+3x^1=6x^3
7y-2y=5y
5y-y=4y

I hope this helped
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Plz help me get the right answer to these
Citrus2011 [14]

- b^{4} + 6b^{3}

divide each term on the numerator by 7b

= - 7b^{5} / 7b + 42b^{4} / 7b

= - b^{4} + 6b^{3}


4 0
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Read 2 more answers
Why do two negatives equal a positive when adding?
alex41 [277]
Two negatives <em>do not </em>equal a positive when adding. If you're in debt and you add more debt, does that get you out of debt?

Two negatives <em>do </em>equal a positive when you're multiplying them together though. This makes sense if you imagine multiplication as squishing or stretching a particular number on the number line. For example, imagine multiplying 2 x 1/2 as <em>squishing </em>the number 2 two times closer to 0. When you multiply 2 by a negative number, say, -1, you squish it so far down that you <em>flip it to the negative side of the number line</em>, bringing it to -2. You can imagine a similar thing happening if you multiply a number like -4 by -2. You squish -4 down to zero, and then <em>flip it to the positive side</em> and stretch it by a factor of 2, bringing it to 8.
4 0
3 years ago
What is the solution to the following system 4x+3y-z=-6
Aliun [14]

Solve equation [2] for the variable  y  
 

<span> [2] y = 6x + 3z - 12 </span>

// Plug this in for variable  y  in equation [1]

<span><span>  [1] 4x + 3•(6x+3z-12) - z = -6 </span><span>  [1] 22x + 8z = 30 </span></span>

// Plug this in for variable  y  in equation [3]

<span><span>  [3] 8x + 2•(6x+3z-12) + 4z = 6 </span><span>  [3] 20x + 10z = 30 </span></span>

// Solve equation [3] for the variable  z  
 

<span> [3] 10z = -20x + 30 [3] z = -2x + 3</span>

// Plug this in for variable  z  in equation [1]

<span><span>  [1] 22x + 8•(-2x+3) = 30 </span><span>  [1] 6x = 6 </span></span>

// Solve equation [1] for the variable  x  

<span><span>  [1] 6x = 6</span>  <span>  [1] x = 1</span> </span>

// By now we know this much :

<span><span>  x = 1</span> <span>  y = 6x+3z-12</span> <span>  z = -2x+3</span></span>

<span>// Use the  x  value to solve for  z  
</span>

<span>   z = -2(1)+3 = 1 </span>

<span>// Use the  x  and  z  values to solve for  y  
</span><span><span>  y = </span>6(1)+3(1)-12 = -3 </span>

Solution :<span><span> {x,y,z} = {1,-3,1}</span> </span>
3 0
3 years ago
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