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3 years ago

Find equation of line HELPP DUE LATE

Mathematics

2 answers:

prisoha [69]3 years ago

8 0

Answer:

y = 3x + 3

Step-by-step explanation:

The equation of a line is: y = mx + c where m is the slope of the line and c is the y-intercept of the line. I will calculate the slope using the points (0, 3) and (1,6)

Slope = $\frac{rise}{run}$

= $\frac{6-3}{1-0}$

= 3

The y-intercept, based on the graph, is 3. Thus, the equation is: y = 3x + 3.

marysya [2.9K]3 years ago

4 0

Y 3x + 3
Give the other person brainliest since they got it first tho!

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a car was bought for 45000 in 2005. if the car loses 4.5% of its value semiannually how much will it be worth at the end of 201

Scorpion4ik [409]

To solve this we are going to use the compounded interest formula: $A=P(1+ \frac{r}{n} )^{nt}$
where
$A$ is the final value of the car after $t$ years
$P$ is the price of the car
$r$ is the rate in decimal form
$n$ is the number of times the rate is compounded per year
$t$ is the time in years

Part 1. Notice that since the car is losing 4.5% of its value semiannually, it is losing 9% annually; also the rate is going to be negative, so $r= \frac{-9}{100} =-0.09$ . Since the car its value semiannually, $n=2$ . Also, to find $t$ , we are going to subtract 2005 from 2017: $t=2017-2005=12$ . Finally, we know for our problem that $P=45000$ . Now that we have all the vales we need, lest replace them in our formula:
$A=P(1+ \frac{r}{n} )^{nt}$
$A=45000(1+ \frac{-0.09}{2} )^{(2)(12)$
$A=45000(0.955)^{24}$
$A=14903.68$

We can conclude that at the end of 2017 the char will be worth $14,903.68

Part 2. Since we want to know the year in which the price of the car will be zero, $A=0$ . From our previous calculations we know that $P=45000$ , $r=-0.045$ ,and $n=2$ . Lets replace those values in our formula one more time:
$A=P(1+ \frac{r}{n} )^{nt}$
$0=45000(1+ \frac{-0.045}{2} )^{2t}$
Since $t$ is the exponent, we are going to use logarithms to bring it down:
$\frac{45000}{0} =(1+ \frac{-0.045}{2} )^{2t}$
$(1+ \frac{-0.045}{2} )^{2t}=0$
$0.9775^{2t}=0$
$ln(0.9775^{2t})=ln(0)$

Since $ln(0)$ cannot be evaluated (you can't divide by zero in mathematics), we can conclude that the value of the car will never be zero.

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3 years ago

You are slowing down if you are:

sergiy2304 [10]

Answer:

B) Decelerating

Step-by-step explanation:

Deceleration occurs when speed starts to reduce. It is the opposite of acceleration

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3 years ago

Read 2 more answers

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