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____ [38]
3 years ago
14

Special right triangles. find the value of x? hypotenuse = leg ×

id="TexFormula1" title=" \sqrt{2} " alt=" \sqrt{2} " align="absmiddle" class="latex-formula">
​

Mathematics
1 answer:
Sonja [21]3 years ago
4 0

Answer:

x = (9√2)/2

Step-by-step explanation:

Reference angle = 45°

Hypotenuse length = 9

Adjacent length = x

Apply the trigonometric ratio CAH:

Cos 45° = Adj/Hyp

Cos 45° = x/9

Multiply both sides by 9

9*Cos 45 = x

9*1/√2 = x (cos 45 = 1/√2)

9/√2 = x

Rationalize

(9*√2)/2 = x

x = (9√2)/2

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