Answer:
the answer is $8,333
Step-by-step explanation:
$200.000 divided by 2 pay checks a month
200.000/24 = 8333.33333 so its $8,333
Answer:
the answer would be $5400
Step-by-step explanation:
5400 times .03 = 162, 162 times 6=972
Answer:
9. 89
Step-by-step explanation:
A squared + B squared = C squared
7 squared + 7 squared = 98 squared
Find the square root of 98 (I recommend using a calculator)
You should get 9.89 as an answer.
Answer:
The value of 7w - 8 is -22
Step-by-step explanation:
Let us solve the question
∵ -4w - 5 = 3
→ Move -5 from the left side to the right side by adding both sides by 5
∴ -4w - 5 + 5 = 3 + 5
∴ -4w = 8
→ Divide both sides by -4
∵
= 
∴ w = -2
→ Now let us find the value of the given expression
∵ The given expression is 7w - 8
→ Substitute w by -2 to gets its value
∴ 7w - 8 = 7(-2) - 8
∴ 7w - 8 = -14 - 8
∴ 7w - 8 = -22
∴ The value of 7w - 8 is -22
Answer:
a) n= 1045 computers
b) n= 442 computers
c) A. Yes, using the additional survey information from part (b) dramatically reduces the sample size.
Step-by-step explanation:
Hello!
The variable of interest is
X: Number of computers that use the new operating system.
You need to find the best sample size to take so that the proportion of computers that use the new operating system can be estimated with a 99% CI and a margin of error no greater than 4%.
The confidence interval for the population proportion is:
p' ±
* 

a) In this item there is no known value for the sample proportion (p') when something like this happens, you have to assume the "worst-case scenario" that is, that the proportion of success and failure of the trial are the same, i.e. p'=q'=0.5
The margin of error of the interval is:
d=
* 



![n= [p'(1-p')]*(\frac{Z_{1-\alpha /2}}{d} )^2](https://tex.z-dn.net/?f=n%3D%20%5Bp%27%281-p%27%29%5D%2A%28%5Cfrac%7BZ_%7B1-%5Calpha%20%2F2%7D%7D%7Bd%7D%20%29%5E2)
![n=[0.5(1-0.5)]*(\frac{2.586}{0.04} )^2= 1044.9056](https://tex.z-dn.net/?f=n%3D%5B0.5%281-0.5%29%5D%2A%28%5Cfrac%7B2.586%7D%7B0.04%7D%20%29%5E2%3D%201044.9056)
n= 1045 computers
b) This time there is a known value for the sample proportion: p'= 0.88, using the same confidence level and required margin of error:
![n= [p'(1-p')]*(\frac{Z_{1-\alpha /2}}{d} )^2](https://tex.z-dn.net/?f=n%3D%20%5Bp%27%281-p%27%29%5D%2A%28%5Cfrac%7BZ_%7B1-%5Calpha%20%2F2%7D%7D%7Bd%7D%20%29%5E2)
![n= [0.88*0.12]*(\frac{{2.586}}{0.04})^2= 441.3681](https://tex.z-dn.net/?f=n%3D%20%5B0.88%2A0.12%5D%2A%28%5Cfrac%7B%7B2.586%7D%7D%7B0.04%7D%29%5E2%3D%20441.3681)
n= 442 computers
c) The additional information in part b affected the required sample size, it was drastically decreased in comparison with the sample size calculated in a).
I hope it helps!