Question

casey bought sandwiches and a bag of chips. Each sandwich cost three times as much as bag of chips. She bought 5 sandwiches for 6 dollars each and spent 42 dollars. How many bags of chips b did she buy?

Answer 1

Answer:

She bought 3 bags of chips .

Step-by-step explanation:

Cost of 1 sandwich = $6

We are given that Each sandwich cost three times as much as bag of chips

So, Cost of a bag of chips = $\frac{6}{3}=2$

Let x be the no. of bags of chips she bought

Now we are given that  She bought 5 sandwiches for 6 dollars each and spent 42 dollars.

Cost of 6 sandwiches = $6 \times 6 = 36$

Cost of x  bags of chips = 2x

ATQ

$36+2x=42$

$2x=6$

$x=3$

Hence she bought 3 bags of chips .

Answer 2

Answer:

4

Step-by-step explanation:

If sandwiches are 6 dollars each, then chips are 3 dollars, she only bought 5 sandwiches for 6 each for 30 dollars(5*6=30).So, she has 12 dollars left to spend since she spent 42 dollars. And 4 *3=12so she only bought 4 bags of chips.