JORDAN LOVVO WHERE ARE YOUUUU

hoa [83]

X= -157 to get that first you need to get 4×88 - 4 = 34 -2x then you do 352 - 4 = 34 - 2x after that do 348 = 34 - 2x then right 2X = 34 - 348 then the last step you do is 2x = -134

5 0

3 years ago

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How do you graph y=2x+4 on a graph

NNADVOKAT [17]

Answer:

y =7 i think. idk im bad at math sorry. lol

7 0

3 years ago

A company must select 4 candidates to interview from a list of 12, which consist of 8 men and 4 women.

Radda [10]

Part A

If 4 candidates were to be selected regardless of gender, that means that 4 candidates is to be selected from 12.

The number of possible selections of 4 candidates from 12 is given by

$^{12}C_4= \frac{12!}{4!(12-4)!}= \frac{12!}{4!\times8!} =11\times5\times9=495$

Therefore, the number of selections of 4 candidates regardless of gender is 495.

Part B:


If 4 candidates were to be selected such that 2 women must be selected, that means that 2 men candidates is to be selected from 8 and 2 women candidates is to be selected from 4.

The number of possible selections of 2 men candidates from 8 and 2 women candidates from 4 is given by

 $^{8}C_2\times ^{4}C_2= \frac{8!}{2!(8-2)!}\times 
\frac{4!}{2!(4-2)!} \\ \\ = 
\frac{8!}{2!\times6!}\times\frac{4!}{2!\times2!} 
=4\times7\times2\times3=168$

Therefore, the number of selections of 4 candidates such that 2 women must be selected is 168.

Part 3:

If 4 candidates were to be selected such that at least 2 women must be selected, that means that 2 men candidates is to be selected from 8 and 2 women candidates is to be selected from 4 or 1 man candidates is to be selected from 8 and 3 women candidates is to be selected from 4 of no man candidates is to be selected from 8 and 4 women candidates is to be selected from 4.

The number of possible selections of 2 men candidates from 8 and 2 women candidates from 4 of 1 man candidates from 8 and 3 women candidates from 4 of no man candidates from 8 and 4 women candidates from 4 is given by

$^{8}C_2\times ^{4}C_2+ ^{8}C_1\times ^{4}C_3+ ^{8}C_0\times ^{4}C_4 \\ \\ = \frac{8!}{2!(8-2)!}\times \frac{4!}{2!(4-2)!}+\frac{8!}{1!(8-1)!}\times \frac{4!}{3!(4-3)!}+\frac{8!}{0!(8-0)!}\times \frac{4!}{4!(4-4)!} \\ \\ = \frac{8!}{2!\times6!}\times\frac{4!}{2!\times2!}+\frac{8!}{1!\times7!}\times\frac{4!}{3!\times1!}+\frac{8!}{0!\times8!}\times\frac{4!}{4!\times0!} \\ \\ =4\times7\times2\times3+8\times4+1\times1=168+32+1=201$

Therefore, the number of selections of 4 candidates such that at least 2 women must be selected is 201.

7 0

3 years ago

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Precipitation for the month of March was 6 1/2 inches less than average. In April, the precipitation was 2 3/8 inches less than

lidiya [134]

Answer:

See explanation.

Step-by-step explanation:

It is subtraction

whole numbers, then numerators.

6 - 2 = 4

1/2 - 3/8

= 4/8 - 3/8 (1/2 = 4/8)

= 1/8

= 4 1/8

hope this helps!

8 0

2 years ago

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Which is true regarding the system of equations? x minus 4 y = 1. 5 x minus 20 y = 4.

goldfiish [28.3K]

Answer:

No solution

Step-by-step explanation:

x - 4y = 1 --> (1)

5x - 20y = 4 --> (2)

y = (¼)x - ¼ --> (1)

y = (¼)x - ⅕ --> (2)

Since these are 2 parallel lines with different y-intercepts, they will never meet

3 0

2 years ago

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