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yaroslaw [1]
3 years ago
9

In PE class, 2 teams are formed for a game of tug of war. Team A can pull with 200 lbs. of force. Team B can pull with 160 pound

s of force and has room for 1 more player. What is the minimum amount the fourth player will need to pull in order for Team B to win? *
A. x ≥ 40
B. x > 40
C. x ≥ 100
D. x > 100
PLEASE HELP FAST!!!!!!!!
Mathematics
1 answer:
noname [10]3 years ago
3 0

Answer:

B. x more than 40

Step-by-step explanation:

If you would like to win the tug of war game, you would have to apply a more greater force to win. If Team B needed to win, over 40 lbs. of force would do.

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Glacier State Bank pays 6% interest, compounded daily. After finding the daily interest rate (to the nearest millionths place) f
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Answer:

The answer is e

Step-by-step explanation: I calculated the percent and none of these match up 6% of 4000 is 240

5 0
3 years ago
ANYONE up???????????????????????????and can i get help with this
Mashcka [7]

Answer:

here's the solution : -

=》2x - 3y = -29

=》x + 6y = 23

=》x = 23 - 6y

now, plugging the value of x in equation 1, we get : -

=》2x - 3y = -29

=》2 (23 - 6y) - 3y = - 29

=》46 - 12y - 3y = -29

=》-15y = -29 - 46

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=》y = 5

now, plugging the value of y as 5 in equation 2

=》x + 6y = 23

=》x + (6 × 5.2) = 23

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8 0
3 years ago
-38--25 +25-50 solve​
adoni [48]

Answer:

<h2>-38</h2>

Step-by-step explanation:

-38-25+25-50

Follow the PEDMAS order of operation

Add and subtract left (left to right )

\mathrm{Apply\:rule\:}-\left(-a\right)\:=\:+a\\-\left(-25\right)=+25\\\\=-38+25+25-50\\=-13+25-50\\-13+25=12\\=12-50\\12-50=-38

4 0
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In a study of the accuracy of fast food​ drive-through orders, one restaurant had orders that were not accurate among orders obs
Evgesh-ka [11]

Answer:Null hypothesis:  

Alternative hypothesis:  

 

 

The p value obtained was a very high value and using the significance level given  we have  so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of orders that were not accurate is not significant different from 0.1 or 10% .  

and the accuracy of the test yes is acceptable since the p value obtained is large enough to fail to reject the null hypothesis

Step-by-step explanation:

Data given and notation n  

n=367 represent the random sample taken

X=32 represent the orders that were not accurate

estimated proportion of orders that were not accurate

is the value that we want to test

represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

 

Alternative hypothesis:  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

(1)  

The One-Sample Proportion Test is used to assess whether a population proportion  is significantly different from a hypothesized value .

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

 

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The significance level provided . The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

 

So the p value obtained was a very high value and using the significance level given  we have  so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of orders that were not accurate is not significant different from 0.1 or 10% .  

3 0
3 years ago
5/22 is that rational number
PIT_PIT [208]
Yes because 5/22 is 4 2/5 and that equals .4
3 0
3 years ago
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