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7nadin3 [17]
2 years ago
13

Which relation is not a function

Mathematics
1 answer:
3241004551 [841]2 years ago
4 0

Answer:

B

Step-by-step explanation:

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Which correlation coefficient best represents a moderate relationship showing fewer anxiety symptoms in people who report higher
weqwewe [10]

Answer:

a) -0.5

Step-by-step explanation:

Correlation

  • Correlation is a technique that help us to find or define a relationship between two variables.
  • It is a measure of linear relationship between two quantities.
  • A positive correlation means that an increase in one quantity leads to an increase in another quantity
  • A negative correlation means with increase in one quantity the other quantity decreases.
  • Values between 0 and -0.3 tells about a weak negative linear relationship, values between -0.3 and -0.7 shows a moderate negative correlation and a correlation value of of -0.7 and -1.0 states a strong negative linear relationship.

Anxiety symptoms and life satisfaction are negatively correlated. As life satisfaction increases the anxiety symptoms decreases.

Thus, a moderate correlation between them can be expressed by a correlation coefficient of -0.5

5 0
3 years ago
A TV that usually sells for $177.13 is on sale for 25% off. If sales tax on the TV is 6%, what is the price of the TV, including
iren [92.7K]

Answer:

b

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
I'm struggling with this lesson on Study Island, please help!
vazorg [7]

Answer:

C

Step-by-step explanation:

Associative property states that when three or more numbers are added, the sum is the same regardless of the grouping.

This means that (4x + 13) + 11 is the same as C. 4x + (13 + 11)

5 0
3 years ago
WILL MARK BRAINLY AND 10 POINTS PLEASE ANSWER I REALLY NEED HELP
GrogVix [38]

Answer:

False, True, True, False

Step-by-step explanation:

I'm pretty sure all your answers are right except the second one. I'm no genus or anything like that tho so I'm not sure. Plus I'm not good at graphs. Well depends how it is.

3 0
3 years ago
It’s a precalculus holiday equation. Need to simplify to find the “secret message” can anyone help???
tensa zangetsu [6.8K]

Take the expression in chunks:

>>

((X+A)(X-A)M+A^2M)E=((X^2-A^2)M+A^2M)E=X^2ME

>>

\dfrac{\frac{R+X}X+\frac X{R-X}}{\frac X{R-X}}=\dfrac{\frac{R+X}X}{\frac X{R-X}}+1

\dfrac{\frac{(R+X)(R-X)}{X(R-X)}}{\frac{X^2}{X(R-X)}}=\dfrac{(R+X)(R-X)}{X^2}=\dfrac{R^2-X^2}{X^2}=\dfrac{R^2}{X^2}-1

\implies\dfrac{\frac{R+X}X+\frac X{R-X}}{\frac X{R-X}}=\dfrac{R^2}{X^2}

>>

Note that (a+b)^2-(a-b)^2=(a^2+2ab+b^2)-(a^2-2ab+b^2)=4ab. So

\displaystyle\frac{4AS}3\sum_{\rm cyc}\frac1{X((E+Y)^2-(E-Y)^2)}=\frac{4AS}3\sum_{\rm cyc}\frac1{4XEY}=\frac{AS}3\sum_{\rm cyc}\frac1{XEY}

where the cyclic sum notation means

\displaystyle\sum_{\rm cyc}f(x,y,z)=f(x,y,z)+f(z,x,y)+f (y,z,x)

In other words, we take the sum over all possible cycles of the sequence of arguments to the summand. The second square-bracketed chunk reduces to

\displaystyle\frac{AS}3\sum_{\rm cyc}\frac1{XEY}=\frac{AS}3\left(\dfrac1{XEY}+\dfrac1{EYX}+\dfrac1{YXE}\right)=\dfrac{AS}3\dfrac3{XEY}=\dfrac{AS}{XEY}

So to recap, we've reduced the starting expression to

X^2ME\left(\dfrac{R^2}{X^2}-\dfrac{AS}{XEY}\right)Y

>>

\dfrac{R^2}{X^2}-\dfrac{AS}{XEY}=\dfrac{R^2EY-ASX}{X^2EY}

Finally, we have

X^2ME\dfrac{R^2EY-ASX}{X^2EY}Y=M(R^2EY-ASX)

Then distributing M and rewriting to decode the message, we have

MERRY-XMAS

6 0
3 years ago
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