Write 2/25 as a decimal and a percent<br><br> i need help

17h +1= [3h-7| for h.

OlgaM077 [116]

Good evening

6 0

3 years ago

The value 9 is 200% of what number?

kykrilka [37]

Answer:

18

Step-by-step explanation:

If 100% is 9 then you need to multiply by 2 to get 200% which is 18.

3 0

3 years ago

Read 2 more answers

34% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a

finlep [7]

Answer:

a) There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

b) There is a 71.62% probability that more than two students use credit cards because of the rewards program.

c) There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

Step-by-step explanation:

There are only two possible outcomes. Either the student use credit cards because of the rewards program, or they use for other reason. So, we can solve this problem by the binomial distribution.

Binomial probability

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem, we have that:

10 student are sampled, so $n = 10$

34% of college students say they use credit cards because of the rewards program, so $\pi = 0.34$

(a) exactly two

This is P(X = 2).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873$

There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

(b) more than two

This is $P(X > 2)$ .

Either a value is larger than two, or it is smaller of equal. The sum of the decimal probabilities must be 1. So:

$P(X \leq 2) + P(X > 2) = 1$

$P(X > 2) = 1 - P(X \leq 2)$

In which

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

So

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 0) = C_{10,0}.(0.34)^{0}.(0.66)^{10} = 0.0157$

$P(X = 1) = C_{10,1}.(0.34)^{1}.(0.66)^{9} = 0.0808$

$P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873$

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0157 + 0.0808 + 0.1873 = 0.2838$

$P(X > 2) = 1 - P(X \leq 2) = 1 - 0.2838 = 0.7162$

There is a 71.62% probability that more than two students use credit cards because of the rewards program.

(c) between two and five inclusive

This is:

$P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873$

$P(X = 3) = C_{10,3}.(0.34)^{3}.(0.66)^{7} = 0.2573$

$P(X = 4) = C_{10,4}.(0.34)^{4}.(0.66)^{6} = 0.2320$

$P(X = 5) = C_{10,5}.(0.34)^{5}.(0.66)^{5} = 0.1434$

$P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.1873 + 0.2573 + 0.2320 + 0.1434 = 0.82$

There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

6 0

3 years ago

a chef uses 5 2/5 pounds of ground beef to make a hamburger and 2 1/4 pounds of ground beef to make meatloaf. the ground beef co

Lisa [10]

Answer:

16 packages

Step-by-step explanation:

5 2/5 + 2 1/4 Use the common denominator of 20

5 8/20 + 2 5/20

7 13/20

I know that I will need 14 packages for the 7 pounds. For the fraction part, 10/20 would be half, so I would need to buy a half pound for that, but I need 13/20 which would be more than a half pound, so I will need to buy 2 more pounds for the fraction part.

14 + 2 = 16

8 0

1 year ago

Help plz:

Mice21 [21]

Step-by-step explanation:

you will see, this is totally easy. so, once you understand that principle, I am sure you will agree with me that this costs more time putting it in here than just doing it yourself in the future.

you need to consider for addition and subtraction every variable combined with an exponent a different thing, a fruit for example.

you know exactly what to do, when you are being asked to add 3 apples to 2 apples, right ?

or, when are are asked to add 4 apples and 2 pears to 3 apples and 2 pears.

in the first case we simply get 5 (2+3) apples.

in the second case we get 7 (3+4) apples and 4 (2+2) pears.

and nothing else happens here.

we could call x² apples, y² pears, y³ plums, x kiwis, t strawberries, t² raspberries. and the constants could be another fruit or grams of sugar.

now, we simply combine the "fruits" that belong together. there is nothing more to this.

5x² + 3y³ - 4x² = x² - 3y³ (because 5-4 for x²)

y³ + 2y³ - 8 + 2 = 3y³ - 6 (1+2 for y³ and -8+2 constant)

9 - 3x - 4x + 2x - 12 = -5x - 3

-6t + 4t² - 6 + 7t - 4t² = t - 6 (4-4 for t², -6+7 for t)

6 0

2 years ago

Write 2/25 as a decimal and a percent i need help