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3 years ago

What is the greatest number of planes determined by four noncollinear points

Mathematics

1 answer:

lilavasa [31]3 years ago

7 0

Answer:

Step-by-step explanation:

Noncollinear points are points that do not lie on the same line.

Each three noncollinear points determine exactly one plane passing through these points.

Let A, B, c and D be four noncollinear points. Suppose that no three points are collinear. Then there can be built 4 planes:

If there are three points which are collinear, then there will be the only plane passing through the line connecting those three points and the fourth point.

Hence, the greatest number of planes determined by four noncollinear points is 4.

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First Question

lower limit of 9 mph $j = 8.5 \ mph$

upper limit of 9 mph $q = 9.5 \ mph$

Second Question

lower limit of 120 pounds is $i = 119.9 \ pounds$

upper limit of 120 pounds is $l = 120.1 \ pounds$

Third Question

lower limit of 187 pounds is $a = 186.75 \ pounds$

upper limit of 187 pounds is $b = 187.25 \ pounds$

Step-by-step explanation:

From the question we are told that

The amount of beer administered is three 12-ounce beers

The amount of coffee administered is two cups of coffee

The speed limit is 60-mph

The smallest unit of scale is 1 mph

The first subject scores 9 mph

Generally given that the smallest unit of scale is 1 mph then the deviation of 9 mph will be by $\frac{1}{2} \ mph$

Hence the lower limit of 9 mph is

$j = 9 - 0.5$

$j = 8.5 \ mph$

And the upper limit of 9 mph is

$q = 9 + 0.5$

$q = 9.5 \ mph$

Generally given that the measuring weight on a scale that is accurate to the nearest 0.2 pound then 120 pounds will deviate by $\frac{1}{0.2} \ pounds$

Hence the lower limit of 120 pounds is

$i = 120 - 0.1$

$i = 119.9 \ pounds$

And the upper limit of 120 pounds is

$l = 120 + 0.1$

$l = 120.1 \ pounds$

Generally given that the measuring weight on a scale that is accurate to the nearest 0.5 pound then 187 pounds will deviate by $\frac{1}{0.5} \ pounds = 0.25 \ pounds$