Answer:
Increase in area of circle is
square mm
Step-by-step explanation:
The actual question is
Find the approximate increase in its area if the radius increases from 20 mm to 22 mm.
Solution
The area of a circle of radius r is given by

Area of circle of radius 20 mm is
square mm
Area of circle of radius 22 mm is
square mm
Increase in area of circle
square mm
Answer:
The expression that represents the number of days until only 10% remains is T((d) 10 %) =100×
.
Step-by-step explanation:
The equation for half life is of the form
A = A₀×
.........................................................................(1)
Where
A = Final amount
A₀ = Initial amount
t = Time
h = Half life
For the equation T(d) = 100×2⁽⁻²⁾....................................(2)
We have by comparison with the equation for half life
2 ≡
and and the equation (2) can be written as
Percentage remaining after 2 half lives is
×100=100×
However if the half life of Technetium-99m is 6 hours then we have for one day
×100=100×
Therefore an expression that represents the number of days until only 10% remains is
×100=100×
= 10 %
=
= ㏑
= ㏑(
)
=
×㏑
= ㏑(
)
=
= 3.322
Therefore the expression for the number of days 10 % of Technetium-99m will be remaining is
T((d) 10 %) =100×
Answer:
8 is 73 corresponding and 9 is 107 supplementary
Step-by-step explanation:
Answer:
y = -2x - 9
Step-by-step explanation:
so we have our two points, (-4,-1) and (-8,7) What we need to do to find our slope is y2 - y1 over x2 - x1. Once plugging in the numbers and subtracting it should give you 8/-4. 8 divided by -4 is -2. m = -2. Now to find our "b" we plug in our slope, and plug in one of the two points into the format of y = mx + b.
-1 = -2(-4) + b
multiply -2 and -4
-1 = 8 + b
we subtract 8 from itself and -1
-9 = b
Our equation is y = -2x - 9