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eduard
3 years ago
15

Examine the diagram, where AB←→ is secant to the circle at points A and B, and CD←→ is secant to the circle at points C and D. T

he lines intersect inside the circle at point P, which is not the center.
A circle with no center shown and two secants as described in the text. Segment B P equals 6, segment C P equals 7, and segment D P equals 12.


What is the length of AP¯¯¯¯¯¯¯¯?
Enter the correct value.

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
5 0

In the secant secant theorem,

AP × BP = CP × DP

AP × 6 = 7 × 12

AP = 7 × 2 = 14

Answer: 14

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Factor the polynomial, x2 + 5x + 6
patriot [66]

Answer:

Choice b.

x^{2} + 5\, x + 6 = (x + 3)\, (x + 2).

Step-by-step explanation:

The highest power of the variable x in this polynomial is 2. In other words, this polynomial is quadratic.

It is thus possible to apply the quadratic formula to find the "roots" of this polynomial. (A root of a polynomial is a value of the variable that would set the polynomial to 0.)

After finding these roots, it would be possible to factorize this polynomial using the Factor Theorem.

Apply the quadratic formula to find the two roots that would set this quadratic polynomial to 0. The discriminant of this polynomial is (5^{2} - 4 \times 1 \times 6) = 1.

\begin{aligned}x_{1} &= \frac{-5 + \sqrt{1}}{2\times 1} \\ &= \frac{-5 + 1}{2} \\ &= -2\end{aligned}.

Similarly:

\begin{aligned}x_{2} &= \frac{-5 - \sqrt{1}}{2\times 1} \\ &= \frac{-5 - 1}{2} \\ &= -3\end{aligned}.

By the Factor Theorem, if x = x_{0} is a root of a polynomial, then (x - x_0) would be a factor of that polynomial. Note the minus sign between x and x_{0}.

  • The root x = -2 corresponds to the factor (x - (-2)), which simplifies to (x + 2).
  • The root x = -3 corresponds to the factor (x - (-3)), which simplifies to (x + 3).

Verify that (x + 2)\, (x + 3) indeed expands to the original polynomial:

\begin{aligned}& (x + 2)\, (x + 3) \\ =\; & x^{2} + 2\, x + 3\, x + 6 \\ =\; & x^{2} + 5\, x + 6\end{aligned}.

4 0
2 years ago
Boston , Massachusetts, and buffalo, New York, are hit by snowstorms that last 3 days . Boston accumulates snow at a rate of 1.5
stich3 [128]

Question is ;

Complete question is;

Boston , Massachusetts, and buffalo, New York, are hit by snowstorms that last 3 days . Boston accumulates snow at a rate of 1.5 feet every 36 hours. Buffalo accumulates snow at a rate of 0.01 inches every minute.

Which city accumulates more snow in 3 days? How much more snow?

Answer:

- Boston accumulates more snow in 3 days.

- It accumulates 0.6 ft of snow more than Boston

Step-by-step explanation:

Boston accumulates 1.5 feet of snow every 36 hours.

Number of hours in 3 days = 24 × 3 = 72 hours.

Thus, In 72 hours, Boston would have accumulated; (1.5 × 72)/36 = 3 feet of snow.

Now, Buffalo accumulates 0.01 inches of snow every minute.

In 3 days, number of minutes we have = 60 × 24 × 3 = 4320 minutes

Thus, total snow accumulated in 3 days = 0.01 × 4320/1 = 43.2 inches

Now, let's convert this to ft;

12 inches = 1ft

Thus; 43.2 inches = 43.2 × 1/12 = 3.6ft

Thus, Buffalo accumulates more snow in 3 days.

It accumulates 0.6 ft of snow more than Boston

3 0
3 years ago
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