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3 years ago

SIMPYFY THE EXPRESSION USING THE ORDER OF OPERATION (7-3)+6/2

Mathematics

2 answers:

kodGreya [7K]3 years ago

8 0

Answer:

Step-by-step explanation:

=(7-3)+6÷2

=(7-3)+3

=4+3

ella [17]3 years ago

5 0

7 bc pemdas so yeah don’t really know what else to say lol

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Through(-2,-3); parallel to 3x+2y=5

Vilka [71]

Step-by-step explanation:

Hey there!

Firstly find slope of the given equation.

Given eqaution is: 3x + 2y = 5.......(i)

Now;

$slope(m1) = \frac{ - coeff. \: of \: x}{coeff. \: of \: y}$

$or \: m1 = \frac{ - 3}{2}$

Therefore, slope (m1) = -3/2.

As per the condition of parallel lines,

Slope of the 1st eqaution (m1) = Slope of the 2nd eqaution (m2) = -3/2.

The point is; (-2,-3). From the above solution we know that the slope is (-3/2). So, the eqaution of a line which passes through the point (-2,-3) is;

(y-y1) = m2 (x-x1)

~ Keep all values.

$(y + 3) = \frac{ - 3}{2} (x + 2)$

~ Simplify it.

$2(y + 3) = - 3x - 6$

$2y + 6 = - 3x - 6$

$3x + 2y + 12 = 0$

Therefore, the eqaution of the line which passes through the point (-2,-3) and parallel to 3x + 2y= 5 is 3x + 2y +12 =0.

Hope it helps...

8 0

3 years ago

Read 2 more answers

At work, Brett must check and record the internal temperature of the freezer on an hourly basis. When working properly, the temp

kiruha [24]

Answer:

Zero

Step-by-step explanation:

The temperature will remain constant over time. This means the slope of the graph will be constant from one point of the graph to the other, which cancels out to zero.

8 0

3 years ago

Need help with this one

Irina-Kira [14]

Answer:

Step-by-step explanation:

Mark as brainliest plz

4 0

2 years ago

Read 2 more answers

Which does not represent an integer?

miv72 [106K]

Answer:

The answer is D

Step-by-step explanation:

Let's see all choices in detail

A . 0 it is correct because 0 is an integer

B .It seems like rational number but it is not simplified yet so -18 \ 2= -9

C .

$\sqrt{9} = 3 \: so \: it \: is \: also \: integer$

D . 4\5 it is decimal so it is rational number not integer

I hope u like it

4 0

3 years ago

1.find the sum. (3^3+5x^2+3x-7)+(8x-6x^2+6) 2. Find the Difference: (8x-4x^2+3\)-(x^3+7x^2+3x-8)

vlada-n [284]

$(3^3+5x^2+3x-7)+(8x-6x^2+6)=\\\\=27\ \underline{+\,5x^2}\ \underline{ \underline{+\,3x}}-7\ \underline{\underline{\,+8x}}\ \underline{-\,6x^2}+6=\\\\=-x^2+11x+26$

or if you mean (3x^3+5x^2+3x-7)+(8x-6x^2+6):

$(3x^3+5x^2+3x-7)+(8x-6x^2+6)=\\\\=3x^3\ \underline{+\,5x^2}\ \underline{ \underline{+\,3x}}-7\ \underline{\underline{\,+8x}}\ \underline{-\,6x^2}+6=\\\\=3x^3-x^2+11x-1$

$(8x-4x^2+3)-(x^3+7x^2+3x-8)=\\\\=\underline{8x}\ \underline{\underline{-\ 4x^2}}+3-x^3\ \underline{\underline{-\,7x^2}}\ \underline{-\,3x}+8=\\\\=-x^3-11x^2+5x+10$

3 0

3 years ago