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uranmaximum [27]
3 years ago
9

47 cm

Mathematics
1 answer:
blondinia [14]3 years ago
4 0

Answer:

I'll setup the problem. But I have a question about the car the equal sides of the isosceles triangle. We'll go with 37 cm

Step-by-step explanation:

you will have to find the areas of the 2 isosceles triangles at either end and the 3 rectangles around the triangles.

Area for the triangles

A =  \frac{1}{2} bh

b = base of triangle, I'll guess it's 24cm

h = height (draw a line between the vertex of the equal sdes to the base at a right angle, then use Pythagoras to

find the height)

h  =  \sqrt{ {37}^{2}  - {( \frac{1}{2}b) }^{2}}

area for rectangles

37x47 + 24x47 + 37x47

sorry it's a little sloppy (I'm on a cellphone)

comment if you have questions

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<h2>Answer:</h2>

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<h2>Step-by-step explanation:</h2>

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Suppose x is a normally distributed random variable with µ = 56 and σ = 3. Find a value x0 of the random variable x that satisfi
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Answer:

a) 52.15

b) 58.53

c) 62.98        

Step-by-step explanation:

We are given the following information in the question:

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Standard Deviation, σ = 3

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Formula:

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P( X < x) = P( z < \displaystyle\frac{x_0 - 56}{3})=0.1  

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b) We have to find x_0 such that

P(X < x)  = 0.8

P( X < x) = P( z < \displaystyle\frac{x_0 - 56}{3})=0.8  

Calculation the value from standard normal z table, we have,  

P(z < 0.842) = 0.8

\displaystyle\frac{x_0 - 56}{3} = 0.842\\\\x_0 = 58.53

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P(X > x)  = 0.01

P( X > x) = P( z > \displaystyle\frac{x - 56}{3})=0.01  

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=P( z \leq \displaystyle\frac{x - 56}{3})=0.99  

Calculation the value from standard normal z table, we have,  

P(z < 2.326) = 0.99

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