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3 years ago

Plz help!!!!! ctc math

Mathematics

1 answer:

bija089 [108]3 years ago

5 0

Answer:

7,13,37,55,103

Step-by-step explanation:

y = 5 + 2x^2

if x =1

y = 5 + 2(1)^2

1^2 = 1

2 x 1 = 2

y=5 + 2 or y = 7

you substatute each one in for x to solve for y

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7. Cell phone plan A costs $30 per month for unlimited calling plus $0.25 per GB of data. Cell phone plan B

Lesechka [4]

Answer:

Part a) The linear model that represents the monthly cost of each plan is

Plan A

$y=0.25g+30$

Plan B

$y=0.15g+40$

Part b) The plans cost the same for 100 GB of data

Step-by-step explanation:

Part a) Write a linear model that represents the monthly cost of each plan if the customer uses g GB of data

Let

g -----> the GB of data

y -----> the monthly cost

we know that

The linear equation that represent each plan is equal to

Plan A

$y=0.25g+30$ ----> equation A

Plan B

$y=0.15g+40$ ----> equation B

Part b) After how many GB of data will the plans cost the same?

Equate equation A and equation B and solve for g

$0.25g+30=0.15g+40$

$0.25g-0.15g=40-30$

$0.10g=10$

$g=100\ GB$

therefore

The plans cost the same for 100 GB of data

7 0

4 years ago

Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .