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Alex73 [517]
3 years ago
14

In the diagram, L= N and would be the Reason for Statement 4? Explain with Stem As WONOM AR

Mathematics
1 answer:
Kryger [21]3 years ago
4 0

Answer:

Option (3)

Step-by-step explanation:

                   Statements                              Reasons

1). ∠L ≅ ∠N                                         1). Given

2). ∠LOM ≅ NMO                              2). Given

3). MO ≅ MO                                     3). Reflexive property of congruence

4). ΔLMO ≅ ΔNOM                           4). AAS postulate of congruence

Therefore, Option (3) will be the correct option.

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What is the product of 2 + 3x and 1 – 4x ?
Alenkinab [10]
Think of it as (-4x+1)(3x+2) then distribute: -4x x 3x= -12x^2, -4x x 2= -8x, 1 x 3x = 3x, and 2 x 1=2. put together all the answers we just got so: -12x^2 - 8x +3x +2 then simplify to get -12x^2 -5x +2
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⚠️⚠️⚠️⚠️BREAKING NEWS A METEOR IS COMING DIRECTLY TOWARDS EARTH THEY ONLY WAY TO STOP THIS METEOR IS BY ANSWERING THIS QUESTION
8090 [49]

The relation {(-1 , 3), (4 , 2), (-1 , 5)} is not a function ⇒ 2nd

Step-by-step explanation:

Let us revise the meaning of relation and function

  • The relation is a set of inputs and outputs
  • A function is a relation with one output for each input, that means every x has only one y
  • Ex: {(2 , 3) , (-1 , -2) , (3 , 2)} is a function because 2 has only 3 , -1 has only -2 and 3 has only 2, {(1 , 7) , (2 , -4) , (1 , -3)} is not a function because 1 has 7 and -3

The relation is a function if and only if every x has only one y

In {(0 , 0), (1 , 0), (2 , 0)}

∵ x = 0 has y = 0

∵ x = 1 has y = 0

∵ x = 2 has y = 0

∴ Every x has only one y

∴ {(0 , 0), (1 , 0), (2 , 0)} is a function

In {(-1 , 3), (4 , 2), (-1 , 5)}

∵ x = -1 has y = 3

∵ x = 4 has y = 2

∵ x = -1 has y = 5

∴ x = -1 has y = 3 and 5

∴ Not every x has only one y

∴ {(-1 , 3), (4 , 2), (-1 , 5)} is not a function

In {(1 , 2), (3 , -5), (-1 , 7)}

∵ x = 1 has y = 2

∵ x = 3 has y = -5

∵ x = -1 has y = 7

∴ Every x has only one y

∴ {(1 , 2), (3 , -5), (-1 , 7)} is a function

In {(7 , -1), (3 , -2), (5 , -2)}

∵ x = 7 has y = -1

∵ x = 3 has y = -2

∵ x = 5 has y = -2

∴ Every x has only one y

∴ {(7 , -1), (3 , -2), (5 , -2)} is a function

The relation {(-1 , 3), (4 , 2), (-1 , 5)} is not a function

Learn more:

You can learn more about the relations and functions in brainly.com/question/10570041

#LearnwithBrainly

6 0
3 years ago
Help me please please​
cupoosta [38]

Answer:

  (7, 5)

Step-by-step explanation:

AC is the resultant. Point C is 7 units right and 5 units up from point A. If those are what go in your boxes, the resultant is ...

  \displaystyle\left(\,7\,\above\,5\,\right)

_____

<em>Comment on the question</em>

Vectors can be represented a number of different ways. Components can be given in rectangular or polar form, and the presentation can be made as a row vector, column vector, sum of orthogonal unit vectors, and other ways. We assume this is supposed to be a column vector of the form ...

  \displaystyle\left(x\above y\right)

7 0
3 years ago
Below is an equation being solved.
Fudgin [204]

Answer:

There are no errors

Step-by-step explanation:

The math is correct

5 0
3 years ago
I need help pls will give you five stars and a big thank you comrade
Zina [86]

Answer:

B, f(x) = ( x+2) ^2(x-1) (x+3)

Step-by-step explanation:

Looking at the x- intercepts, the line passes at 2, -1, and 3, so B is you answer (:

3 0
3 years ago
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