ExerciseChange 40days to weeks and days
1 answer:
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<u>answer:</u>
<u>work:</u>
| subtract 5x and move it over to the 7x, and solve
| subtract 4 and move it over to the 10, and solve
| divide by 2
| final answer
hope this helps! ❤ from peachimin
Answer:
Step-by-step explanation:
Hello!
The variable of interest is
Y: speed of language development on children
Factor: number of siblings
Levels of factors:
Single birth
Twins
Triplets
The claim is that the more siblings the child has, the slower he develops language abilities.
The hypotheses for the ANOVA are:
H₀: μ₁= μ₂= μ₃
H₁: At least one of the population means is different.
α: 0.05
p-value= 0.0217
Using the p-value approach the decision rule is
p-value ≤ α, reject the null hypothesis.
p-value > α, do not reject the null hypothesis.
The p-value is less than the significance level, the decision is to reject the null hypothesis.
At 5% level of significance you can conclude that there is significance differences between the population means of language development on children of single birth, twins and triplets.