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3 years ago

Find the measure of angle X

Mathematics

2 answers:

stich3 [128]3 years ago

6 0

According to the picture, you can assume that angle X is congruent to angle Y due to their triangle shape. Here is the work:

1. Set the equations equal to one another: 4x-8 = 2x

2. Move the variables to get the "x" values on one side: 2x = 8

3. Divide by 2 to get "x": x = 4

4. Plug in "x" into the Angle X equation: 4(4)-8 = angle x....16-8....8

Angle X is 8 degrees. Hope this helped :)

sergij07 [2.7K]3 years ago

4 0

angle x would be 8 degrees :)

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Write the slope-intercept form of the equation that passes through the point (4, -2) and is perpendicular to the line y =4x - 1

ExtremeBDS [4]

Answer:

Step-by-step explanation:

If two lines are perpendicular then the product of theirs slopes is equal -1:

y=m₁x+b₁ ⊥ y=m₂x+b₂ ⇒ m₁×m₂ = -1

y = 4x - 2 ⇒ m₁=4

4×m₂ = -1 ⇒ m₂ = -¹/₄

The line y=-¹/₄x+b passes through point (4, -2) so the equation:

-2 = -¹/₄×4 + b must be true

-2 = -1 + b

b = -1

Therefore equation in slope-intercept form:

y = -¹/₄x - 1

4 0

3 years ago

Ok... so I failed my math test because I wasnt at school for a week and didn't know anything....

ozzi

When multiplying two powers with the same base (which is 5 in this case) you can simply add the exponents. - 8 + 4 = - 4. The answer is
${5}^{ - 4}$

8 0

3 years ago

Find side lengths C and H

Nuetrik [128]

Answer:

$\displaystyle c=\frac{2\sqrt{3}}{3}\\\\\displaystyle h=7\sqrt{2}\\$

Step-by-step explanation:

<u>Right Triangles</u>

A right triangle can be identified by the fact it has an internal angle of 90°. In a right triangle, the trigonometric ratios stand.

Let's consider the triangle to the left. We need to calculate side c, one of the legs of the triangle. We can use the angle adjacent to it (60°) or the angle opposite to it (30°) with the appropriate trigonometric ratio.

We'll use the adjacent angle, and

$\displaystyle tan60^o=\frac{2}{c}$

Solving for c

$\displaystyle c=\frac{2}{tan60^o}=\frac{2}{\sqrt{3}}$

Rationalizing

$\displaystyle c=\frac{2}{\sqrt{3}}\cdot \frac{\sqrt{3}}{\sqrt{3}}=\frac{2\sqrt{3}}{3}$

Now for the triangle to the right. The side h is the hypotenuse. Again, any of the two angles can be used (though they are equal, for it's an isosceles triangle). For any of them it is true that

$\displaystyle sin45^o=\frac{7}{h}$