The function can use all values of x which means x is in between -inf and +inf. The first option expresses this.
Multiply entire equation by (x-2)(x+1) to get rid of the denominators That would lead to X(x+1)+(x-1)(x-2)=-1(x-2)(x+1)
Finally, using distributive property and foil, you would get x^2+x+x^2-3x+2=(-x^2+x+2).2x^2-2x+2=-x^2+x+23x^2-3x=0
3x(x-1)x=0 and x=1
You must follow the steps below:
1. First, you should apply the dstributive property:
=(x²-<span>8x+15/3x)(8x/x-3)
=(8</span>x³-64x²+120x)/3x(x-3)
2. As you can see, the common factor in the numerator is: "8x". So, you have:
=8x(x²-8x+15)/3x(x-3)
3. Then, when you simplify, you obtain:
=8(x²-8x+15)/3(x-3)
Therefore, the solution is: 8(x²-8x+15)/3(x-3)
Answer:
0
Step-by-step explanation:
6+(-6)= 6-6=0
