All categories

2 years ago

PLeassssse HELPPPP!!!

Mathematics

1 answer:

Genrish500 [490]2 years ago

4 0

Answer:

B i believe is the answer

Step-by-step explanation:

You might be interested in

Kendrick received 24 fewer e-mails than he did on Thursday. If he received a total of 126 e-mails on those two days, how many di

telo118 [61]

E+(e-24)=126

2e-24=126

2e=150

e=75

So (s)he recieved 75 and 75-24=51 emails on those days.

3 0

3 years ago

Together donkey and Shrek can make 7 cupcakes in 12 mins. Shrek can make 2 cupcakes in 8 mins. How long will it take Donkey to m

katrin [286]

Multiply 7 x 12 which is 84, 8x2 is 16, 16 divded by 3 is 5, so 5 minutes

3 0

2 years ago

Determine the number of solutions for the equation shown below.

Stolb23 [73]

Answer:

A. 0

Step-by-step explanation:

Nothing can be equal to itself if you subtract 9 from it.

6 0

2 years ago

Construct the discrete probability distribution for the random variable described. Express the probabilities as simplified fract

lisov135 [29]

Answer:

$P(X = 0) = 0.03125$

$P(X = 1) = 0.15625$

$P(X = 2) = 0.3125$

$P(X = 3) = 0.3125$

$P(X = 4) = 0.15625$

$P(X = 5) = 0.03125$

Step-by-step explanation:

For each toss, there are only two possible outcomes. Either it is tails, or it is not. The probability of a toss resulting in tails is independent of any other toss, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Fair coin:

Equally as likely to be heads or tails, so $p = 0.5$

5 tosses:

This means that $n = 5$

Probability distribution:

Probability of each outcome, so:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.5)^{0}.(0.5)^{5} = 0.03125$

$P(X = 1) = C_{5,1}.(0.5)^{1}.(0.5)^{4} = 0.15625$

$P(X = 2) = C_{5,2}.(0.5)^{2}.(0.5)^{3} = 0.3125$

$P(X = 3) = C_{5,3}.(0.5)^{3}.(0.5)^{2} = 0.3125$

$P(X = 4) = C_{5,4}.(0.5)^{4}.(0.5)^{1} = 0.15625$

$P(X = 5) = C_{5,5}.(0.5)^{5}.(0.5)^{0} = 0.03125$

5 0

2 years ago

~HELP PLEASE~<br> What is the value of X?

SashulF [63]

I don’t know but your in higher math than me so can you help me on my questions please. Sorry I know that seems kinda selfish but I need help. I know how you feel. No one will help me.

3 0

3 years ago

Read 2 more answers