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Serga [27]
3 years ago
8

Simplify 9 to the 2nd over 9 to the 7th. 95 1 over 9 to the 9th 1 over 9 to the negative 5th 1 over 9 to the 5th

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
5 0
\bf ~~~~~~~~~~~~\textit{negative exponents}\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}\\\\
-------------------------------\\\\
\cfrac{9^2}{9^7}\implies \cfrac{1}{9^{-2}9^7}\implies \cfrac{1}{9^{-2+7}}\implies \cfrac{1}{9^5}\implies \cfrac{1}{59049}
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Step-by-step explanation:

1.\\\\2^x=64,\\\log 2^x=\log64,\\x\log 2=\log 64,\\x=\frac{\log 64}{\log 2}=\boxed{6}

2.\\x=\left(\frac{2}{5}\right)^3=\frac{2^3}{5^3}=\boxed{\frac{8}{125}}

3. This problem incorporates an exponent property.

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Read 2 more answers
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