Let’s take x as the price of a taco and y as the price of a serving of nachos.
22x + 17y = 71.05. First order
10x + 5y = 27.25. Second order
Multiply the first order by 5 and the second order by 11
110x + 85y = 355.25
110x + 55y = 299.75
Subtract
30y = 55.5
y = 1.85
So 10x + 5x1.85 = 27.25
10x = 27.25 - 9.25 = 18
x = 1.8
So each taco cost $1.80 and an order of nachos cost $1.85
Answer:
97,99,101,103
Step-by-step explanation:
Let x = first odd integer
x+2 = 2nd odd integer
x+4 = 3rd odd integer
x+6 = 4th odd integer
Sum of 4 odd integers is 400
x+ (x+2) + (x+4)+(x+6) = 400
Combine like terms
4x +12 = 400
Subtract 12 from each side
4x+12-12 = 400-12
4x = 388
Divide by 4 on each side
4x/4 = 388/4
x=97
The first integer is 97
The 2nd is 97+2 =99
The third ix 97+4 = 101
The 4th is 97+6 = 103
Answer:
f (k)
Step-by-step explanation:
By the segment addition postulate,
AC + CE = AE so AC = AE - CE
AC = (x+50) - (x+32)
AC = x+50-x-32
AC = 18