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Alona [7]
2 years ago
7

five note cards each contain a different single-digit numbers.The cards are arranged to find the largest possible 5-digit number

,then rearanged to find the smallest possible 5 digit number. the sum of these two numbers is 99089. what is the SUM of the 5 digits on the cards?
Mathematics
1 answer:
Mashutka [201]2 years ago
3 0

Solution: The largest number is 86521, the smallest number is 12568  and the sum of digits is 22.

Explanation:

Let the digits on cards be a, b, c, d and e. where a>b>c>d>e>0 because if the smallest digit is 0, then we get a four digit number on rearrangement.

To get the five digit greatest number we have to arrange these digits in descending order. So the greatest number is abcde.

To get the five digit greatest number we have to arrange these digits in descending order. So the smallest number is edcba.

It is given that the sum of greatest and smallest number is 99089.

When we add greatest and smallest number we noticed that the sum of c and c is 2c which is equal to 0. It is possible if c=0 or c=5. since c>0, therefore the value of c=5.

So the from the addition of unit digits we get e+a=9, there are many possibilities to get the sum 9 like 1+8, 2+7 and 3+6 because a>5 and e<5 since we have to find the greatest and smallest number so by hidden trial the value of e=1 and a=8. Similarly d+b=8, b>5 and d<5 by hidden trial the value of b=2 and d=6.

The digits are 8, 6, 5, 2 and 1, therefore  largest number is 86521, the smallest number is 12568  and the sum of digits is 22.

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Answer: ? Maybe 3???

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Katyanochek1 [597]

Using the z-distribution, the p-value would be given as follows:

b) 0.0086.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis we test if the means are equal, hence:

H_0: \mu_D - \mu_C = 0

At the alternative hypothesis, it is tested if they are different, hence:

H_1: \mu_D - \mu_C \neq 0

<h3>What are the mean and the standard error for the distribution of differences?</h3>

For each sample, they are given as follows:

  • \mu_D = 12, s_D = \frac{5.2}{\sqrt{73}} = 0.6086
  • \mu_C = 14, s_C = \frac{4.1}{\sqrt{81}} = 0.4556

Hence, for the distribution of differences, they are given by:

  • \overline{x} = 12 - 14 = -2.
  • s = \sqrt{0.6086^2 + 0.4556^2} = 0.76

<h3>What is the test statistic?</h3>

The test statistic is given by:

z = \frac{\overline{x} - \mu}{s}

In which \mu = 0 is the value tested at the null hypothesis.

Hence:

z = \frac{\overline{x} - \mu}{s}

z = \frac{-2 - 0}{0.76}

z = -2.63.

Using a z-distribution calculator, for a two-tailed test, with z = -2.63, the p-value is of 0.0086.

Hence option B is correct.

More can be learned about the z-distribution at brainly.com/question/13873630

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4 0
2 years ago
2.8, 3.4, 4.0, 4.6, . . . Write an equation for the nth term of the arithmetic sequence. Then find a50.
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Answer:

a_n = 2.2 + 0.6 n

a_50 = 32.2

Step-by-step explanation:

What's the common difference of this series?

a_1 = 2.8

a_2 = 3.4

Common difference = a_2 - a_1 = 3.4 - 2.8 = 0.6.

Expression for the nth term:

a_n = a_1 + (n - 1) \cdot\text{Common Difference} \\\phantom{a_n } = 2.8 + 0.6 \; (n-1) \\\phantom{a_n} = 2.8 + 0.6 \; n - 0.6\\\phantom{a_n} = 2.2 + 0.6\; n

n = 50 for the fiftieth term. Therefore

a_{50} = 2.2 + 0.6 \times 50 = 32.2.

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Answer:

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Step-by-step explanation:

Let x be the number of adult tickets and y be the number of children's tickets.

We are given that there are total 12 people. Therefore, we can set:

x+y=12

Moreover, we are given that an adult ticket costs $21.50 and a child's ticket costs $14.75, therefore, cost of x adult tickets will be 21.50x and cost of y children's ticket will be 14.75y. We can form the second equation by setting the total cost of tickets as:

21.50x+14.75y=204

Therefore, the required system of equations that could be used to find x and y will be:

x+y=12

21.50x+14.75y=204

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