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kolbaska11 [484]
3 years ago
5

write an equation in point-slope form and slope-intercept form for a line that passes through point(4,-1) and has a slope of -3

Mathematics
1 answer:
melamori03 [73]3 years ago
3 0

Answer:

Point Slope: (y-(-1)=3(x-4)

Step-by-step explanation:

y-y1=m(x-x1) Point Slope Form\\plug in:\\y-(-1)=3(x-4)\\

Slope Intercept is y=mx+b\\Find Y Int (b):\\b=-13\\Plug in;\\y=3x-13

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How do I solve this 4/5 -3/9 I solve
Oksana_A [137]

Answer:

21/45

Step-by-step explanation:

You make the denominator the same and u also multiply the top too and u subtract and thats how u get the answer

3 0
3 years ago
Read 2 more answers
A fruit bowl contains 2 bananas, 5 oranges, and 4 apples in the simplest form, what is the ratio of apples to bananas in the fru
prisoha [69]

Answer:

Ratio of apple to banana is 2:1

Step-by-step explanation:

To find ratio of x type of one thing and y type of other thing we divide

x by y and ratio is written as

ratio = x:y

_________________________________

Number  of banana = 2

Number  of apples = 4

Ratio of apple to banana = Number  of apples :Number  of banana

Ratio of apple to banana = 4:2

since 4 is divisible by 2 , to get the ratio in simplest form

we divide both numerator and denominator by 2

Ratio of apple to banana = 4/2:2 /2 = 2:1

Thus,

Ratio of apple to banana is 2:1

3 0
3 years ago
PLZ HELP ME! Whoever gets it right will be marked brainiest
Brut [27]

Answer:

Probability that Hannah only has to buy 3 or less boxes before getting a prize is 0.784

Step-by-step explanation:

Given, 40% of cereal boxes contain a prize

⇒probability of getting a prize on opening a box, P(A)=0.4

where A is the event of getting a prize on opening a cereal box

and probability of not getting a prize on opening a box, P(A')=1-P(A)=0.6

where A' is the event of not getting a prize on opening a cereal box

This problem needs to be divided into 3 situation:

  • Case 1, Where Hannah gets prize when she buys the first box:

Let K be the event of Hannah winning the prize on buying the first box.

⇒P(K)=P(A)=0.4

  • Case 2, Where Hannah gets prize when she buys the second box:

I<u>n this event Hannah should not get the prize in first box but should get the prize on buying the second box</u>

Let L be the event of Hannah winning the prize on buying the second box

So, P(L)=P(A')·P(A)

           =(0.6)·(0.4)

           =0.24

  • Case 3,Where Hannah gets prize when she buys the third box:

<u>In this event Hannah should not get the prize in first and second box but should get the prize on buying the third box</u>

Let L be the event of Hannah winning the prize on buying the third box

So, P(L)=P(A')·P(A')·P(A)

           =(0.6)·(0.6)·(0.4)

           =0.144

Let N be the event of Hannah winning the prize on buying 3 or less boxes before getting a prize

⇒N=K∪L∪M

Now, Required probability is P(N)=P(K∪L∪M)=P(K)+P(L)+P(M) [As events K,L and M are independent and disjoint events]

⇒P(N)=0.4+0.24+0.144

         =0.784

7 0
3 years ago
Find all solutions in radian [0,2pi) solve 4sinx= -cos^2x +4
Sphinxa [80]
I hope this helps you


-cos²x= sin²x-1


4.sinx = sin²x-1+4


sin²x-4.sinx +3=0


(sinx-3)(sinx-1)=0


sinx≠3


sinx =1


SİN90=1


8 0
3 years ago
Segment Segment X Y is dilated through point M with a scale factor of 2. Which segment shows the correct result of the dilation?
Vedmedyk [2.9K]

Answer:

segment BF

Step-by-step explanation:

3 0
2 years ago
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