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soldier1979 [14.2K]
3 years ago
9

For questions 9-16 solve the inequality

Mathematics
1 answer:
eduard3 years ago
6 0

Answer:

9. 4x<12

10. x (greater than or equal to) 6

11. 9x>36

12. x (greater than or equal to) -5

13. x>15

14. x (less than or equal to) -30

15. x>-48

16. x<1

Step-by-step explanation:

i hope this helps :)

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konstantin123 [22]

Answer:

The answer to your question is:  (4, -1)

Step-by-step explanation:

M = midpoint   (-1, 1)

A = (-6, 3)

B = (x, y)

xm = \frac{x1 + x }{2}

x = 2xm - x1

x = 2(-1) + 6

x = -2 + 6

x = 4

ym = \frac{y1 + y }{2}

y = 2ym - y1

y = 2(1) - 3

y = 2 - 3

y = -1

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3 years ago
A water park charges $5 for entry into the park and an additional $2 for each of the big water slides. Steven spent $17 on his v
morpeh [17]
LET X= ADDITIONAL AMOUNT
<u>EQAUTION=</u> 5+2x=17
                      -5       -5
                    __________
                      2x=12
                     _______
                      2     2
                       X=6 IS THE ANSWER. HOPE THIS HELPS!!!!!
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2 years ago
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Desi is about to dilate ABC by multiplying each coordinate by d.
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The function in Exercise represents the rate of flow of money in dollars per year. Assume a 10-year period at 8% compounded cont
anzhelika [568]

Answer:

a) The present value is 688.64 $

b) The accumulated amount is 1532.60 $

Step-by-step explanation:

<u>a)</u><u> The preset value equation is given by this formula:</u>

P=\int^{T}_{0}f(t)e^{-rt}dt

where:

  • T is the period in years (T = 10 years)
  • r is the annual interest rate (r=0.08)

So we have:

P=\int^{T}_{0}(0.01t+100)e^{-rt}dt

Now we just need to solve this integral.

P=\int^{T}_{0}0.01te^{-rt}dt+\int^{T}_{0}100e^{-rt}dt

P=e^{-0.08t}(-1.56-0.13t)|^{10}_{0}+1250e^{-0.08t}|^{10}_{0}

P=0.30+688.34=688.64 $

The present value is 688.64 $

<u>b)</u><u> The accumulated amount of money flow formula is:</u>

A=e^{r\tau}\int^{T}_{0}f(t)e^{-rt}dt

We have the same equation but whit a term that depends of τ, in our case it is 10.

So we have:

A=e^{r\tau}\int^{T}_{0}(0.01t+100)e^{-rt}dt=e^{0.08\cdot 10}P

A=e^{0.08\cdot 10}688.64=1532.60 $

The accumulated amount is 1532.60 $

Have a nice day!

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Answer:foot

Step-by-step explanation:

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