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3 years ago

For questions 9-16 solve the inequality

Mathematics

1 answer:

eduard3 years ago

6 0

Answer:

9. 4x<12

10. x (greater than or equal to) 6

11. 9x>36

12. x (greater than or equal to) -5

13. x>15

14. x (less than or equal to) -30

15. x>-48

16. x<1

Step-by-step explanation:

i hope this helps :)

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konstantin123 [22]

Answer:

The answer to your question is: (4, -1)

Step-by-step explanation:

M = midpoint (-1, 1)

A = (-6, 3)

B = (x, y)

$xm = \frac{x1 + x }{2}$

x = 2xm - x1

x = 2(-1) + 6

x = -2 + 6

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y = 2ym - y1

y = 2(1) - 3

y = 2 - 3

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LET X= ADDITIONAL AMOUNT
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The function in Exercise represents the rate of flow of money in dollars per year. Assume a 10-year period at 8% compounded cont

anzhelika [568]

Answer:

a) The present value is 688.64 $

b) The accumulated amount is 1532.60 $

Step-by-step explanation:

a) The preset value equation is given by this formula:

$P=\int^{T}_{0}f(t)e^{-rt}dt$

where:

T is the period in years (T = 10 years)
r is the annual interest rate (r=0.08)

So we have:

$P=\int^{T}_{0}(0.01t+100)e^{-rt}dt$

Now we just need to solve this integral.

$P=\int^{T}_{0}0.01te^{-rt}dt+\int^{T}_{0}100e^{-rt}dt$

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The present value is 688.64 $

b) The accumulated amount of money flow formula is:

$A=e^{r\tau}\int^{T}_{0}f(t)e^{-rt}dt$

We have the same equation but whit a term that depends of τ, in our case it is 10.

So we have:

$A=e^{r\tau}\int^{T}_{0}(0.01t+100)e^{-rt}dt=e^{0.08\cdot 10}P$

$A=e^{0.08\cdot 10}688.64=1532.60 $$

The accumulated amount is 1532.60 $

Have a nice day!

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Answer:foot

Step-by-step explanation:

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