Do 96 divided by 6.
6 goes into 96 16 times. therefore, your answer is 16
Answer:
v > -25/p
r = -5 +7/3 w
Step-by-step explanation:
- pv + 40 < 65
Subtract 40 from each side
- pv + 40-40 < 65-40
-pv < 25
Divide each side by -p (remember to flip the inequality since we are dividing by a negative)
-pv/-p > 25/-p
v > -25/p
7w - 3r = 15
Subtract 7w from each side
7w-7w - 3r = 15-7w
-3r = 15-7w
Divide by -3
-3r/-3 = (15-7w)/-3
r = -5 +7/3 w
Answer:
![A^{-1}=\left[\begin{array}{cc}-3&-4\\1&1\end{array}\right]](https://tex.z-dn.net/?f=A%5E%7B-1%7D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-3%26-4%5C%5C1%261%5Cend%7Barray%7D%5Cright%5D)
message SHOW_ME_THE_MONEY_
Step-by-step explanation:
The matrix
![A=\left[\begin{array}{cc}1&4\\-1&-3\end{array}\right]\rightarrow |A|=(1 \times -3)-(-1\times 4)=1\\\rightarrow A^{-1}=\left[\begin{array}{cc}-3&-4\\1&1\end{array}\right] \\](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%264%5C%5C-1%26-3%5Cend%7Barray%7D%5Cright%5D%5Crightarrow%20%7CA%7C%3D%281%20%5Ctimes%20-3%29-%28-1%5Ctimes%204%29%3D1%5C%5C%5Crightarrow%20A%5E%7B-1%7D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-3%26-4%5C%5C1%261%5Cend%7Barray%7D%5Cright%5D%20%5C%5C)
We can check that in fact A*A^⁻1=I_2 the identity matrix of size 2 x 2.
Now the message was divided in 1 x 2 matrices, then we have that the sequence given is the result of multiplying m by A, so to get m again we multiply now by A^⁻1. and we get the next table
Encoded message Decoded message message in letters by association
11 52 19 8 S H
-8 -9 15 23 O W
-13 -39 0 13 _ M
5 20 5 0 E _
12 56 20 8 T H
5 20 5 0 E _
-2 7 13 15 M O
9 41 14 5 N E
25 100 25 0 Y _
Then the message decoded is SHOW_ME_THE_MONEY_
The given function f(x) = |x + 3| has both an absolute maximum and an absolute minimum.
What do you mean by absolute maximum and minimum ?
A function has largest possible value at an absolute maximum point, whereas its lowest possible value can be found at an absolute minimum point.
It is given that function is f(x) = |x + 3|.
We know that to check if function is absolute minimum or absolute maximum by putting the value of modulus either equal to zero or equal to or less than zero and simplify.
So , if we put |x + 3| = 0 , then :
± x + 3 = 0
±x = -3
So , we can have two values of x which are either -3 or 3.
The value 3 will be absolute maximum and -3 will be absolute minimum.
Therefore , the given function f(x) = |x + 3| has both an absolute maximum and an absolute minimum.
Learn more about absolute maximum and minimum here :
brainly.com/question/17438358
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