Solve each equation for the 1) g=C+a, for a

In the figure to the right, if AC=19 and BC=16, what is the radius? *For a circle*

ch4aika [34]

Answer:

The radius of the circle is 10.2 units

Step-by-step explanation:

The complete question is

In the figure to the right, if AC=19 and BC=16, what is the radius?

A circle has center A. Points B and D are on the circle, with B on the left and D near the bottom. Point C lies outside the circle such that the line segment A C passes through point D and the line segments A B and B C form a right angle.

The radius is approximately (Round to the nearest tenth as needed.)

The picture of the question in the attached figure

we know that

In the right triangle ABC

Applying the Pythagorean Theorem

$AC^2=AB^2+BC^2$

substitute the given values

$19^2=AB^2+16^2$

solve for AB

$AB^2=19^2-16^2$

$AB^2=105\\AB=10.2\ units$

Remember that the radius is the same that the segment AB

therefore

The radius of the circle is 10.2 units

6 0

3 years ago

In triangle ABC, angle A is 25 degree, and Angle B is 105 degrees. what is the measure of angle c

Scilla [17]

Angle c= 60°

This is because 105+25+x=180°
Hope this helps and good luck!! :)

8 0

3 years ago

Raul had $60. Mike had $30. Each boy donated 1 tenth of his money.

Sav [38]

Answer:

raul donated more money than mike did is

Step-by-step explanation:

raul donated 1/10 of 60 so

1/10*60=6

mike donated 1/10 of 30 so

1/10*30=3

so raul donated more money than mike did is the correct statement

5 0

3 years ago

Read 2 more answers

Determine for each x-volume wether it is in the domain of f or not

Vera_Pavlovna [14]

-2 is the only domain I think. The rest are not. Hope I’ve helped.

4 0

3 years ago

The vertex of this parabola is at (3,5) when the y-value is 6 the x value -1 what is the coefficient of the squared term in the

ale4655 [162]

Answer:

1/16

Step-by-step explanation:

Here,

Vertex =(3,5)

x= -1, y=6

Simply,eqn of parabola is given by ax^2+bx+c=y

So, coefficient of squared term (x^2) is 'a'

Therefore, we've to find the value of a

Moving on to solution:

a-b+c=6 ___(i) (by putting the given values of x and y in eqn of parabola )

We know that,

Vetex=(-b/2a, ( 4ac-b^2)/4a)

(3,5) = (-b/2a , (4ac-b^2)/4a)

Equating corresponding sides,we get

3= -b/2a

b=-6a___(ii)

Again,

5=(4ac-b^2)/4a

5=(4ac/4a) - (b^2/4a)

5= c- (36a^2/4a) (by putting value of b from eqn ii )

5= c-9a___(iii)

Now,moving back to the first eqn

a+6a+5+9a=6

16a=1

therefore,a=1/16

Hence ,the required value of coefficient of squared term is 1/16.

I tried my best to give clear explanation as much as I know. It's just we've have to find the value of a . For that, you can use any method you find easier.

3 0

3 years ago