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3 years ago

If a snail crawls 12 centimeters per hour, how long will it take for the snail to travel 1 meter

Mathematics

1 answer:

Pavlova-9 [17]3 years ago

5 0

Answer: 8 1/3 hours or 500 minutes

Step-by-step explanation:

Keep in mind that there are 100 centimeters in a meter.

The snail moves at a pace of 12 cm/h, and needs to go 100 cm. You can just divide 100/12 to get 8 1/3, which is how many hours (groups of 12 cm) it takes for the snail to travel 100 cm (1 meter).

If necessary, you can also multiply 8 1/3 by 60 to get the number of minutes the snail takes. 8 times 60 is 480, and 1/3 of an hour is 20, so add 480+20 to get 500 minutes.

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Find the x and y intercepts of the equation 8x+y=-9

Juliette [100K]

Answer:

see explanation

Step-by-step explanation:

To find the intercepts, that is where the graph crosses the x and y axes.

• Let x = 0, in the equation for y-intercept

• Let y = 0, in the equation for x-intercept

x = 0 : 0 + y = - 9 ⇒ y = - 9 ⇒ (0, - 9 ) ← y- intercept

y = 0 : 8x + 0 = - 9 ⇒ x = - $\frac{9}{8}$ ⇒ ( - $\frac{9}{8}$ , 0) ← x- intercept

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2 years ago

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Mark's dad is three times older than Mark. Mark's sister is 2 years younger than Mark. (3m) The sum of their ages is 48. How old

nataly862011 [7]

Answer:

Age of Mark $=10$ years

Age of Mark's dad $=30$ years

Age of Mark's sister $=8$ years

Step-by-step explanation:

Let age of Mark be $x$ years.

Mark's dad is three times older than Mark

Age of her Mark's dad $=3x$

Mark's sister is 2 years younger than Mark

Age of Mark's sister $=(x-2)$ years

The sum of their ages is 48.

$x+3x+x-2=48\\5x-2=48\\5x=50\\x=10$

Age of Mark $=x=10$ years

Age of Mark's dad $=3x=3(10)=30$ years

Age of Mark's sister $=x-2=10-2=8$ years

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

find the equation of the sides of an isosceles right angled triangle whose vertex is (-2,-3) and the base is on the line x=0

Serggg [28]

Answer:

AC:y=x-1 CB:y=-x-5 AB:x=0

Step-by-step explanation:

Consider the triangle. The base AB is on the line x=0, the vertex C is (-2,-3)

The side AC is equal to BC. The angle ACB is 90 degrees. If the base is on the line x=o, it is on the axis Y.Explore the distance from the point C to the AB

c(-2,-3), the distance to the axis Y is equal to the modul of the coordinate x (-2), it is 2. The coordinates of point projected by the point C to the axis Y is N(0,-3). The modul of the height is 2, the height of the isosceles triangle to the base is the bisectrix, so the angle BCA is 90/2=45degrees, CBA is 180-90-45=45 degrees too

the heigt CN is equal to side NB, NB=2

Suppose B is (0,y) (x=0 because the base is on this line)

THe modul of the vector NB is equal to sqrt ((0-0)^2+(y+3)^2)= 2

modul (y+3)= 2

y=-1 or y=-5

(0,-1), (0,-5) - two points, one of them (suppose B) is (0,-5) when A is (0,-1) (A is remote from the point N on the same distance with B, because AB is the median too)

Find CB and AC

Use the equation for AC

(x-0)/(-2-0)= (y+1)/(-3+1)

x/-2= (y+1)/-2

x=y+1

y=x-1

For CB

(x-0)/ (-2-0)= (y+5)/ (-3-(-5))

x/-2= (y+5)/2

-x=y+5

y=-x-5

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2 years ago