All categories

3 years ago

IF PASSPORT is written as RCUURQTV, then how will BOOKLET be coded?

Mathematics

1 answer:

TiliK225 [7]3 years ago

7 0

Answer: DQQMNGV

Step-by-step explanation: Each letter is shifted two letters to the right on a letter strip (a -> b -> c), so BOOKLET would be DQQMNGV.

Hope this helps!

You might be interested in

Please help me solve this problem.

Igoryamba

Answer:

The value of x will be:

$x=22\sqrt{2}$

$x = 31.1$

Step-by-step explanation:

Given

a = 22

b = 22

To determine

hypotenuse x = ?

For a right-angled triangle with sides, a and b the hypotenuse c is defined as

$c=\sqrt{a^2+b^2}$

substituting a = 22, b = 22 and c = x

$x=\sqrt{22^2+22^2}$

$x=\sqrt{22^2\cdot \:2}$

Apply radical rule: $\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0$

$x=\sqrt{2}\sqrt{22^2}$

$x=22\sqrt{2}$

$x = 31.1$

Therefore, the value of x will be:

$x=22\sqrt{2}$

$x = 31.1$

7 0

3 years ago

The area of a triangular roof section with a base of 7 feet and a height of 3.5 is

trasher [3.6K]

C 12.5 because you do 7*3.5/2

8 0

3 years ago

Y = 7 - 3x<br> Non linear or linear?<br> Thanks in advance

ASHA 777 [7]

Answer:

Non linear( it doesn't go through the 0

Step-by-step explanation:

6 0

3 years ago

Write an equivalent expression for the 4th root of 324m^12 * the cubed root of 64k^9. Need help!

Elis [28]

Answer:

The equivalent expression to the givan expression is

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}=12\sqrt[4]{4}m^3k^3$

Step-by-step explanation:

Given expression is 4th root of 324m^12 * the cubed root of 64k^9

The given expression can be written as

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}$

To find the equivalent expression to the given expression :

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}$

$=\sqrt[4]{81\times 4m^{12}}\times\sqrt[3]{16\times 4k^9}$

$=\sqrt[4]{3\times 3\times 3\times 3\times 4m^{12}}\times\sqrt[3]{4\times 4\times 4k^9}$

$=(3\times \sqrt[4]{m^{12}})\times (4\times \sqrt[3]{k^9})$

$=(3\times \sqrt[4]{4m^{12}})\times (4\times \sqrt[3]{k^9})$

$=(3\times \sqrt[4]{4}\times (m^{12})^{\frac{1}{4}})\times (4\times {(k^9)^{\frac{1}{3}})$

$=(3\sqrt[4]{4}\times m^{\frac{12}{4}})\times (4\times k^{\frac{9}{3}})$

$=(3\sqrt[4]{4}\times m^3)\times (4\times k^3)$

$=3\sqrt[4]{4}m^3.4k^3$

$=12\sqrt[4]{4}m^3k^3$

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}=12\sqrt[4]{4}m^3k^3$

Therefore the equivalent expression to the given expression is

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}=12\sqrt[4]{4}m^3k^3$

8 0

3 years ago

Please let me know thank u

Andru [333]

Answer:

I'm pretty sure it's 4 because the graph is proportional

Step-by-step explanation:

5 0

3 years ago

IF PASSPORT is written as RCUURQTV, then how will BOOKLET be coded?​

IF PASSPORT is written as RCUURQTV, then how will BOOKLET be coded?