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blagie [28]
3 years ago
11

Let f of x equals the integral from x to 1 of the square root of the quantity of 1 plus t squared . use your calculator to find

f'(1)

Mathematics
1 answer:
ollegr [7]3 years ago
8 0

Analytically, it will be

-√(1+1²) = -√2

The calculator shows it to be -1.41421356237

_____

= -√2 to 12 significant digits.

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Stella [2.4K]
Answer: (2b+7)(5a-3)
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Find the circumference and area of a circle with a diameter of 22 inches. Leave your answers in terms of pi.
Gnesinka [82]
The answer for this will be letter d. C = 22π and A = 121π. This is computed using the formula of C= Dπ which is C = (22)π. On the other hand, the area of this circle is computed by using the formula A = <span>πr^2. This is computed as follows:
A = </span><span>πr^2
A = </span><span>π (22/2)^2
A = </span><span>π (11)^2
</span>A = 121<span>π</span><span>

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4 0
3 years ago
A scatter plot was made to show the value of certain cars based on the age of the car in years. The equation of the scatter plot
Mashutka [201]
Am not sure but I think it C
6 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%28sinx%5E%7B2%7D%20theta%29%5Cfrac%7Bx%7D%7By%7D%281%2Bcostheata%29" id="TexFormula1" title="
beks73 [17]

The result of expanding the trigonometry expression \sin^2(\theta) * (1 + \cos(\theta)) is cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)

<h3>How to evaluate the expression?</h3>

The expression is given as:

\sin^2(\theta) * (1 + \cos(\theta))

Express \sin^2(\theta) as 1 - \cos^2(\theta).

So, we have:

\sin^2(\theta) * (1 + \cos(\theta)) =  (1- \cos^2(\theta)) * (1 + \cos(\theta))

Open the bracket

\sin^2(\theta) * (1 + \cos(\theta)) =  1 + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)

Express 1 as cos°(Ф)

\sin^2(\theta) * (1 + \cos(\theta)) =  cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)

Hence, the result of expanding the trigonometry expression \sin^2(\theta) * (1 + \cos(\theta)) is cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)

Read more about trigonometry expressions at:

brainly.com/question/8120556

#SPJ1

3 0
2 years ago
The function h(x)=x^2+3 and g(x)=x^2-6. if g(x)=h(x)+k, what us the value of k
lutik1710 [3]

Answer:

The value of k is -9

Step-by-step explanation:

Subsitute

g(x)=h(x)+k

(x^2-6)=(x^2+3)+k

x^2-6=x^2+3+k

subtract x^2+3 from both sides (or add -x^2-3 to both sides)

-9=k

k=-9

3 0
3 years ago
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