Normally 7 envelopes but on rare occasions, there may be more due to If the packages are filled with Envelopes. Also depending on if the 7 packages are boxes of envelopes, and in that case, 140 envelopes times 7, which would be 980 envelopes in the 7 packages. 140 * 7 = 980.
The chances that NEITHER of these two selected people were born after the year 2000 is 0.36
<h3>How to determine the probability?</h3>
The given parameters are:
Year = 2000
Proportion of people born after 2000, p = 40%
Sample size = 2
The chances that NEITHER of these two selected people were born after the year 2000 is calculated as:
P = (1- p)^2
Substitute the known values in the above equation
P = (1 - 40%)^2
Evaluate the exponent
P = 0.36
Hence, the chances that NEITHER of these two selected people were born after the year 2000 is 0.36
Read more about probability at
brainly.com/question/25870256
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Answer:
![\sqrt[3]{0.95} \approx 0.9833](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B0.95%7D%20%5Capprox%200.9833)
![\sqrt[3]{1.1} \approx 1.0333](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1.1%7D%20%5Capprox%201.0333)
Step-by-step explanation:
Given the function: ![g(x)=\sqrt[3]{1+x}](https://tex.z-dn.net/?f=g%28x%29%3D%5Csqrt%5B3%5D%7B1%2Bx%7D)
We are to determine the linear approximation of the function g(x) at a = 0.
Linear Approximating Polynomial,
a=0
![g(0)=\sqrt[3]{1+0}=1](https://tex.z-dn.net/?f=g%280%29%3D%5Csqrt%5B3%5D%7B1%2B0%7D%3D1)
Therefore:
(b)![\sqrt[3]{0.95}= \sqrt[3]{1-0.05}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B0.95%7D%3D%20%5Csqrt%5B3%5D%7B1-0.05%7D)
When x = - 0.05
(c)
(b)![\sqrt[3]{1.1}= \sqrt[3]{1+0.1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1.1%7D%3D%20%5Csqrt%5B3%5D%7B1%2B0.1%7D)
When x = 0.1
