Simplify 3 square root of 20/ square root of 5

Mathematics

1 answer:

7nadin3 [17]3 years ago

8 0

-7√5

rewrite 20 as 2^2·5

factor 4 out of 20. negative ∛4(5)-√5

rewrite 4 and 2^2 negative ∛2^2·5-√5

pull terms out from under the radical

-3(2√5)√5

multiply 2 by -3

-6√5-√5

subtract √5 from -6√5

-7√5

the answer is -7√5

You might be interested in

Solve for x 4^x-2=256

salantis [7]

We can do this problem using two ways....
Let me show you both methods.

Method 1: "Without using logs"

$4^{x-2}=256\\\\ 4^{x-2}=4^4\ \ \ \ \ |\because 4^4 \ $is the same as 256$

Now, since both sides of the equation have same base and they equal each other, then their exponent must be equal to each other. So, we equal their exponents.

After equaling the exponents, we get,
$x - 2 = 4 \\\\ x=4+2 \\\\ \boxed{x = 6} \Leftarrow $ This is your answer!!$

Now,
Method 2: "Using Logs"

$4^{x-2}=256 \\\\ ~~~~~~~\Downarrow ~~~~~~ is\ the\ same\ thing\ as\ saying \\\\$log\ _4\ 256 =x-2 \\\\ Now,\ using\ the\ log\ property\ log_AB= \frac{log_cA}{log_cB}, \ we \ get, \\\\ \frac{log_{10}256}{log_{10}4}=x-2 \\\\ 4=x-2 \\\\ 4+2=x\\\\ 6=x \\\\ \boxed{x=6} \Leftarrow $This is your answer$

So, either way we get x= 6

8 0

3 years ago

Read 2 more answers

Solve for x. 7x/2+5=8

finlep [7]

Answer:

x=6/7

Step-by-step explanation:

7x÷2+5=8

divide by 2 on both sides:

7x/2+5=8(it's a fraction)

subtract 5 on both sides