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mixas84 [53]
3 years ago
14

Find the height and the exact area of the isosceles trapezoid.

Mathematics
1 answer:
kipiarov [429]3 years ago
8 0
I’m going to go with 77 i’m pretty sure
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Find the total cost to the nearest cent. (Examples
Hunter-Best [27]

Answer:

$58x.20=11.6

$58.00+11.60= $69.60

Step-by-step explanation:

5 0
3 years ago
PLEASE HELP MATH:(:(:(:(
kotykmax [81]
So 0.081 x=38,900 so x (#sold to date) = 480,247 would be the answer.
5 0
3 years ago
15 points because I need it quickly!! I will give brainliest to first answer
Zolol [24]

Answer:

12.60

Step-by-step explanation:

3 0
3 years ago
2x + 4y-31=123 what is the equation for x and then y​
UNO [17]

Answer:

i would say

y = ( 77 - x ) / 2

Step-by-step explanation:

2x + 4y = 123 + 31

2x +4y = 154

4y = 154 -2x

y = ( 154 - 2x ) / 4

y = ( 77 - x ) / 2

6 0
3 years ago
The Arc Electronic Company had an income of 7676 million dollars last year. Suppose the mean income of firms in the same industr
garri49 [273]

Answer:

0.9772 = 97.72% probability that a randomly selected firm will earn more than Arc did last year

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Suppose the mean income of firms in the same industry as Arc for a year is 90 million dollars with a standard deviation of 7 million dollars.

This means that \mu = 90, \sigma = 7

What is the probability that a randomly selected firm will earn more than Arc did last year?

Arc earned 76 million, so this is 1 subtracted by the pvalue of Z when X = 76.

Z = \frac{X - \mu}{\sigma}

Z = \frac{76 - 90}{7}

Z = -2

Z = -2 has a pvalue of 0.0228

1 - 0.0228 = 0.9772

0.9772 = 97.72% probability that a randomly selected firm will earn more than Arc did last year

3 0
3 years ago
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