The answer to the problem is 2,677 mi
<h2>Frequency of allele </h2>
Explanation:
Hardy Weinberg Equilibrium is used to calculate the allelic as well as genotypic frequency
Allelic frequency of dominant and recessive allele is represented by p and q respectively whereas genotypic frequency of dominant genotype is represented by
and
respectively
Given:
H allele (p) = hairy heffalump (dominant)
h allele (q) = hairless heffalump (recessive)
36% of heffalump population is hairless represents the % of recessive genotype, hh (
) =36%
Calculation of frequency of the h allele (q) :
Frequency of genotype hh (
) will be: 36/100=0.36 or 0.6*0.6
Frequency of h allele (q) will be 0.6
Radius temperature and brightness
<span>Blood is a liquid and has cellular parts. The liquid contains substances such as proteins and lipids. The cellular constituents are erythrocytes (red blood cells), leukocytes and platelets.</span>