Momentum = mass * velocity

50 meters in 5 seconds = 50/5 = 10 m / second

Required momentum = 200*10 = 2,000

I cant remember how to write the units for this.

5 0

3 years ago

Can someone help me with is one

ch4aika [34]

Answer:

C is your answer

Step-by-step explanation:

7 0

3 years ago

What is the distance covered by a train while slowing down from

alukav5142 [94]

Answer:

The distance covered is 113.75 m

Step-by-step explanation:

As per the question:

The initial velocity of the train, v = 20 m/s

The final velocity of the train, v' = 6 m/s

Uniform deceleration, a = 1.6 $m/s^{2}$

Or uniform acceleration, a = - 1.6 $m/s^{2}$

Here, the body decelerates, i.e., slows down at a uniform rate thus we take acceleration with negative sign.

Now, to find the distance covered, s:

Using the eqn of Kinemetics:

$v'^{2} = v^{2} + 2as$

$6^{2} = 20^{2} + 2(- 1.6)s$

$36 - 400 = - 3.6s$

$s = \frac{- 364}{- 3.6} = 113.75\ m$

5 0

3 years ago