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Ilya [14]
3 years ago
6

Determine the value of c for each figure

Mathematics
1 answer:
erica [24]3 years ago
6 0

Answer:

can you tell me a little bit more?

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Jade types 40 words in 7 minutes. Andrew types 35 words in 6 minutes. Who is the faster typist?
GREYUIT [131]

Andrew types faster than Jade

40/7 = 5.7 words per minute (Jade)

35/6 = 5.8 words per minute (Andrew)

May I have brainliest please? :)

6 0
2 years ago
Read 2 more answers
If the numerator and denominator of the fraction is increased by 2an1 respectively; it becomes3/4 if the numerator and the denom
ipn [44]

Answer:

The fraction is\frac{7}{1}

Step-by-step explanation:

Let the numerator be x and denominator be y

So, Fraction = \frac{x}{y}

Now we are given that numerator and denominator of the fraction is increased by 2 and 1 respectively. it becomes 3/4

So, Fraction becomes :\frac{x+2}{y+1}=\frac{3}{4}

4(x+2)=3(y+1)

4x+8=3y+3

4x-3y+5=0----1

We are also given that the numerator and the denominator are decreased by 2 and 1 respectively , it becomes 1/2

So, Fraction becomes :\frac{x-2}{y-1}=\frac{1}{2}

2(x-2)=y-1

2x-4=y-1

2x-y-3=0 ---- 2

Substitute the value of y from 2 in 1

4x-3(2x-3)+5=0

4x-6x+9+5=0

14=2x

7=x

Substitute the value of x in 2

2(2)-y-3=0

4-3=y

1=y

So, Fraction = \frac{x}{y}=\frac{7}{1}

Hence The fraction is\frac{7}{1}

7 0
3 years ago
Use the function to fill in the blanks in the table.
S_A_V [24]

Answer:

gnrg

Step-by-step explanation:

5 0
3 years ago
2m3 of soil containing 28% silt was mixed into 1 m3 of soil containing 13% of silt. What is the silt content mixture?
Leto [7]
Alright
so
28% of 2 m³=0.28 times 2=0.56 m³ of silt in the first mixture

13% of the 1 m³=0.13 times 1=0.13 m³ of silt in 2nd

total is 0.56 m³+0.13 m³=0.69 m³ of silt
and the total is 2m³+1m³=3m³

so
0.69/3=0.23=23%

answer is D
6 0
3 years ago
Nevermind, i solved my problem
bezimeni [28]

Answer:

What was the problem?

Step-by-step explanation:

Oh ok , I G u e s s it is solved already.

8 0
3 years ago
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