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2 years ago

I need help what is p(x)?

Mathematics

1 answer:

Andreyy892 years ago

4 0

Answer:

Step-by-step explanation:

p(x) = r(x) - c(x)

p(x) = (11x) - (6x + 20)

Remove the first set of parentheses because they are unnecessary.

p(x) = 11x - (6x + 20)

To remove the second set of parentheses, you must distribute the negative sign throughout the parentheses.

p(x) = 11x - 6x - 20

Combine like terms.

p(x) = 5x - 20

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Brad bought 70.030 m of chain to make necklaces. He used 0.667 m of the chain to make one necklace.

Margaret [11]

Brad bought 70.030m of this chain to make a necklace, then he used 0.667m of it to make one, and how much he had left, the key word ''used'' and have left'' means subtract so all we have to do is subtract 70.030m minus 0.667m and we get the answer.

Answer: 69.363m of his chain is left.

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3 years ago

Which of the following is in order from largest to smallest?

daser333 [38]

Step-by-step explanation:

9,7,-1,-2..................

5 0

2 years ago

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Task:

Elan Coil [88]

Answer:

318 days or 10.6 months,

No, because the time between august and december is 8 months and it would take 10 to complete the tunnel

Step-by-step explanation:

start by determining the slope:

subtract the remaining distance from the total distance to determine distance so far, then divide by time.

m = (3200 - 1700)/5

m = 1500/5

m = 300

y = mx + b

Plug in to solve for x.

3200 = 300x + 0

3200 = 300x

divide y by m. This is x. (this is known as inverse operation if you didnt know already.)

3200 = 300(10.6_)

8 0

2 years ago

First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x

e-lub [12.9K]

Answer:

$(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C$

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

$\int x ln(5+x)dx$

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

$\int (U-5) ln(U)dU$

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

$\int (pq')=pq-\int qp'$

so we must define p, q, p' and q':

p=ln U

$p'=\frac{1}{U}dU$

$q=\frac{U^{2}}{2}-5U$

q'=U-5

and now we plug these into the formula:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU$

Which simplifies to:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU$

Which solves to:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C$

so we can substitute U back, so we get:

$\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C$

and now we can simplify:

$\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C$

$\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C$

$\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C$

notice how all the constants were combined into one big constant C.

7 0

3 years ago

What is the interest on RS. 1000 at 10 p.c.p.a for 1 year.

Delicious77 [7]

Answer:

Interest wil be 10% of 100 which is 10

So,

interest will be Rs.10

and total amount to be payed will be 100+10 which is Rs.110

3 0

3 years ago

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